Java内存游戏如何翻转单个卡？

Question

当我点击一张卡片时，我试图翻转它们。当我点击所有卡片时，所有卡片同时翻转

这是我的密码。任何帮助都将不胜感激，并提前向您表示感谢

package cards;

import processing.core.PApplet;

public class MemoryGame extends PApplet {

static final int COLS=2;
static final int RAWS=3;
Card[] cards;

public void setup() {
    size(RAWS*Card.WIDTH, COLS*Card.HEIGHT); // card witdth 60*9+(10*9) for the gaps=630
    cards = new Card[COLS*RAWS];
    cards[0] = new Card(11, 0, 0);
    cards[1] = new Card(3, Card.WIDTH, 0);
    cards[2] = new Card(7, 2 * Card.WIDTH, 0);
    cards[3] = new Card(3, 0, Card.HEIGHT);
    cards[4] = new Card(7, Card.WIDTH, Card.HEIGHT);
    cards[5] = new Card(11, 2 * Card.WIDTH, Card.HEIGHT);

}

public void draw() {
    background(204);
    for (int i = 0; i < 6; i++) {
        cards[i].display(this);
    }
}

public void mousePressed() {
    for (int i = 0; i < 6; i++) {
        cards[i].flip();
    }
}

public static void main(String[] args) {
    PApplet.main("cards.MemoryGame");
}
}

+++++++++++++++++++++++++++++++++卡类++++++++++++++++++++++++++++++++++++++++++++++++++++++

package cards;

import processing.core.PApplet;

public class Card {

boolean shown=false;
static final int WIDTH = 120;
static final int HEIGHT = 180;
static final int gap = 20;
int value;
float x,y;   

Card(int _v, float _x, float _y) {

    value = _v;
    x = _x;
    y = _y;
}

public void display(PApplet applet) {
   applet.stroke(0);
    applet.strokeWeight(2);
    if (shown) {
        applet.fill(100);
        applet.rect(x, y, WIDTH, HEIGHT,WIDTH/5);
       applet.textAlign(applet.CENTER,applet.CENTER);
       applet.textSize(WIDTH/2);
       applet.fill(0);
       applet.text(value,x+WIDTH/2,y+HEIGHT/2);
    } else {
        applet.fill(255);
        applet.rect(x, y, WIDTH, HEIGHT,WIDTH/5);
    }
}



public void flip() {
    shown=!shown;
}
}

Answer 1

这是因为当你按下一张卡片时，你会在每张卡片上循环

public void mousePressed() {
    for (int i = 0; i < 6; i++) {
        cards[i].flip();
    }
}

尝试定义您单击的卡，并仅对该卡使用翻转方法

Answer 2

当按下鼠标按钮时，您正在翻转所有卡片。 您必须检查鼠标位置是否与卡相交，并按下鼠标，如果是，则翻转该卡。 生成方法mouseX（）和mouseY（），它们为您提供鼠标坐标。 只需添加if（鼠标位置与卡相交）：

    public void mousePressed() {
    for (int i = 0; i < 6; i++) {
        if(mouseX() >= cards[i].x && mouseX() <= cards[i].x+cards[i].width && mouseY() >= cards[i].y && mouseY() <= cards[i].y+card[i].height) {
            cards[i].flip();
        }
    }
}

Answer 3

您需要在mousePressed（）方法中获取鼠标事件，这样您就可以确定单击了哪张卡，从而可以翻转它。 尝试实现java。awt。MemoryGame类中的MouseListener接口

Answer 4

在mousePressed方法中循环遍历所有卡片并翻转它们。你以为会发生什么

我想你要检查用户点击的位置，然后翻转位于该位置的卡