基于作者姓名的java Jersey消息筛选应返回多个值

Question

public Message getMessageByAuthor(String authorName) { 
    List<Message> nameList = new ArrayList<Message>(messages.values());
    Message message = null;
    if (!authorName.isBlank()) {
        Iterator<Message> iterator = nameList.iterator();
        while (iterator.hasNext()) {
            message = iterator.next();
            if (message.getMessageAuthor().contains(authorName)) {
                return message;
            }
        }
    }
    return message;
}

Answer 1

正如评论中提到的Triby，您应该创建一个新列表，添加符合条件的元素，然后返回该列表，以便在匹配的情况下获得多个元素

public List<Message> getMessageByAuthor(String authorName) { 
    List<Message> nameList = new ArrayList<Message>(messages.values());
    List<Message> responseMessageList = new ArrayList<>();
    Message message = null;
    if (!authorName.isBlank()) {
        Iterator<Message> iterator = nameList.iterator();
        while (iterator.hasNext()) {
            message = iterator.next();
            if (message.getMessageAuthor().contains(authorName)) {
                 responseMessageList.add(message);
            }
        }
    }
    return responseMessageList;
}