java如何使用SeleniumWebDriver检查webtable中的webelements是否按字母顺序排序？

Question

我们的应用程序包含web元素表。我的目的是检查目录是否按字母顺序排列

WebDriver d=new FirefoxDriver();
d.get("http://www.javatpoint.com/wrapper-class-in-java");

WebElement table=d.findElement(By.xpath(".//*[@id='city']/table/tbody"));
List<WebElement> lst=table.findElements(By.tagName("tr"));
System.out.println(lst);

List ls=new ArrayList<String>();
for(int i=0;i<=6;i++)
{
    ls=lst.addAll(get(i).getText())
}

我的目标是在一个列表中存储字符串类型的webelement，并创建另一个排序类型的列表 最后比较两个列表。请帮忙

Answer 1

Collections.sort(SortedList,String.CASE_INSENSITIVE_ORDER);  

只是即兴创作，我们需要添加String.CASE_INSENSITIVE_ORDER以匹配区分大小写的排序

Answer 2

您可以将默认排序存储在类似obtainedList的字符串数组中，然后使用sortedList的集合对其进行排序，最后两者都进行排序

ArrayList<String> obtainedList = new ArrayList<>(); 
List<WebElement> elementList= driver.findElements(By.xpath(YourLocator));
for(webElement we:elementList){
   obtainedList.add(we.getText);
}
ArrayList<String> sortedList = new ArrayList<>();   
for(String s:obtainedList){
sortedList.add(s);
}
Collections.sort(sortedList);
Assert.assertTrue(sortedList.equals(obtainedList));

对于降序添加：

Collections.reverse(sortedList);

在Collections.sort(sortedList);之后

Answer 3

public boolean sortVerify() {
    List<WebElement> theList=driver.findElements(By.xpath("//*[@id='productView']/div/div/div/div"));
    List<Integer> Prices=new ArrayList<>();

    for (int NumberOfItem=1; NumberOfItem<theList.size();NumberOfItem++) {
        System.out.println("feteching by xpath price");
        String priceOneRaw=driver.findElement(By.xpath("//*[@id=\"p_"+NumberOfItem+"_1\"]/div/div[5]/div/span[1]")).getText();
        System.out.println("feteching by xpath price    "+priceOneRaw);
        ////below 2 lines are to get the price in exact integers, as earlier it was in format Rs.3829.
    String priceOneFinal=priceOneRaw.replaceAll("[\\-\\?\\+\\.\\^:,\\\u20B9]","");
    String PriceComplete = priceOneFinal.split("Rs")[1];
    int finalPrice=Integer.parseInt(PriceComplete);
    Prices.add(finalPrice);
    }

    int previousPrice=Prices.get(0);
    for(int SortCheckNumber=1;SortCheckNumber<theList.size()-1;SortCheckNumber++) {
        if(Prices.get(SortCheckNumber)<previousPrice) {
            System.out.println("notSorted");
            return false;
        }else {
            previousPrice=Prices.get(SortCheckNumber);
        }

    }
    System.out.println("allSorted");
    return true;
}