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单击“创建新帐户”时java应用程序崩溃

每当我单击“创建新帐户”按钮时,应用程序就会崩溃。Logcat中的错误表明我需要调用FirebaseApp。初始化(这个);我已经这么做了,但还是发生了同样的错误。这是我的注册活动

private FirebaseAuth mAuth;
private ProgressDialog loadingbar;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_register);

    FirebaseApp.initializeApp(this);
    mAuth = FirebaseAuth.getInstance();

我的日志在下面

 Process: com.example.whatsappclone, PID: 9246
java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.whatsappclone/com.example.whatsappclone.RegisterActivity}: java.lang.IllegalStateException: Default FirebaseApp is not initialized in this process com.example.whatsappclone. Make sure to call FirebaseApp.initializeApp(Context) first.
    at 安卓.app.ActivityThread.performLaunchActivity(ActivityThread.java:2913)
    at 安卓.app.ActivityThread.handleLaunchActivity(ActivityThread.java:3048)
    at 安卓.app.servertransaction.LaunchActivityItem.execute(LaunchActivityItem.java:78)
    at 安卓.app.servertransaction.TransactionExecutor.executeCallbacks(TransactionExecutor.java:108)
    at 安卓.app.servertransaction.TransactionExecutor.execute(TransactionExecutor.java:68)
    at 安卓.app.ActivityThread$H.handleMessage(ActivityThread.java:1808)
    at 安卓.os.Handler.dispatchMessage(Handler.java:106)
    at 安卓.os.Looper.loop(Looper.java:193)
    at 安卓.app.ActivityThread.main(ActivityThread.java:6669)
    at java.lang.reflect.Method.invoke(Native Method)
    at com.安卓.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:493)
    at com.安卓.internal.os.ZygoteInit.main(ZygoteInit.java:858)
 Caused by: java.lang.IllegalStateException: Default FirebaseApp is not initialized in this process com.example.whatsappclone. Make sure to call FirebaseApp.initializeApp(Context) first.
    at com.google.firebase.FirebaseApp.getInstance(com.google.firebase:firebase-common@@16.0.2:240)
    at com.google.firebase.auth.FirebaseAuth.getInstance(Unknown Source:1)
    at com.example.whatsappclone.RegisterActivity.onCreate(RegisterActivity.java:36)
    at 安卓.app.Activity.performCreate(Activity.java:7136)
    at 安卓.app.Activity.performCreate(Activity.java:7127)

共 (3) 个答案

  1. # 1 楼答案

    也许你拼错了什么。错误显示:

    FirebaseApp.initializeApp(this) 
    

    当您在描述FirebaseApp中陈述时。初始化(这个)

  2. # 2 楼答案

    确保您添加了这一行-apply plugin:'com。谷歌。gms。谷歌服务在应用程序gradle的末尾

    dependencies {
    ....
    }
    apply plugin: 'com.google.gms.google-services'
    

    然后创建一个扩展应用程序类的子类,并在那里创建这个Firebase实例

    public class MyApp extends Application {
    @Override
    public void onCreate() {
        super.onCreate();
        FirebaseApp.initializeApp(this);
     }
    }
    

    如果您不知道如何创建应用程序类及其用法,此post可能会对您有所帮助

  3. # 3 楼答案

    在创建任何活动之前,可能在应用程序级别初始化Firebase:

    <application
        android:name="MyApp"
        [...]
    
    public class MyApp extends Application {
        @Override
        public void onCreate() {
            super.onCreate();
            FirebaseApp.initializeApp(this);
        }
    }