重复java中已经满足的循环

Question

我期待着重复一个“游戏”，如果它已经在我的情况下，用户猜测随机数感到满意。我不知道从哪里返回到主游戏，除非我必须在其中创建另一个“do-while”循环，并在其中显示： System.out.println("you have tried: " + count + " times. Would you like to play again? y/n")的部分重新键入游戏。有没有一种方法可以直接回到实际的猜测循环，而不是创建另一个循环？ 希望有意义

import java.util.Scanner;
import java.util.concurrent.ThreadLocalRandom;

public class pass {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        String pass = "password123";
        String input;
        int guess;
        int count;
        count = 0;
        int num;


        do {
            System.out.print("Enter your password: ");
            input = scanner.next();

        } while (!input.equals(pass));
        System.out.println("Correct! Now play the guess game! Guess a number between 1 - 10.");
        do {
            num = ThreadLocalRandom.current().nextInt(1,10);
            guess = scanner.nextInt();
            count++;
            if (guess == num) {
                System.out.println(" Well done!");
                **System.out.println("you have tried: " + count + " times. Would you like to play again? y/n");**
            }
            else if (guess < num) {
                System.out.println("your number is smaller than the number given");
            }
            else {
                System.out.println("your guess is too high");
            }

        } while (guess != num);



    }
}

Answer 1

如果您想重用代码，您可以创建函数（或方法，因为我们在一个类中）。它们可以用来封装代码，并从任何地方调用代码来使用它

您可以定义这样的方法：

public static void methodName() {
    // code go here
}

然后，你可以在任何地方这样称呼它：

pass.methodName(); // It will execute the code inside methodName()

实际上，这比这要复杂得多，您可以给方法赋值并返回其他方法，更改其范围使其仅为内部的或可由其他类访问。但我想你是个初学者，所以我保持简单。我强烈建议您快速研究一下面向对象编程

对于您的代码，您可以将游戏的while循环放入一个方法中，并在开始时和每次玩家想要重新启动游戏时调用它。祝你的比赛好运

Answer 2

我设法做到了这一点。这似乎是可行的，但有一件事让我失望，在最后一次，当我在“n”或其他键，而不是“y”Exception in thread "main" java.util.InputMismatchException。有没有更柔和的方法来完成它

import java.util.Scanner;
import java.util.concurrent.ThreadLocalRandom;

public class pass {


    public static void randomnum(){
        Scanner scanner = new Scanner(System.in);
        int guess;
        int count;
        count = 0;
        int num;
        do {
            num = ThreadLocalRandom.current().nextInt(1,10);
            guess = scanner.nextInt();
            count++;
            if (guess == num) {
                System.out.println(" Well done!");
                System.out.println("you have tried: " + count + " times.");
                String answer;
                do{
                    System.out.println("Do you want to play again? y/n");

                    answer = scanner.next();
                    if (answer.equals("y")) {
                        System.out.println("let's play again");
                        randomnum();
                        System.out.println("Correct! Now play the guess game! Guess a number between 1 - 10.");
                    }
                    else {
                        System.out.println("you are logout!");
                        break;
                    }

                }while (answer.equals("Y"));
                randomnum();
            }
            else if (guess < num) {
                System.out.println("your number is smaller than the number given");
            }
            else {
                System.out.println("your guess is too high");
            }

        } while (guess != num);
    }
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        String pass = "password123";
        String input;



        do {
            System.out.print("Enter your password: ");
            input = scanner.next();

        } while (!input.equals(pass));
        System.out.println("Correct! Now play the guess game! Guess a number between 1 - 10.");
        randomnum();

    }
}

Answer 3

最简单的解决方案是将整个“猜测循环”移动到一个单独的方法中。然后，如果希望它重复，只需递归调用该方法