有 Java 编程相关的问题?

你可以在下面搜索框中键入要查询的问题!

java JTable排序错误后添加行

我有一个JTable和它setAutoCreateRowSorter(true),这样我可以对行进行排序。在不使用排序的情况下向表中添加行时,效果很好。但是,当我首先对表进行排序时(只需单击列标题,行就会被排序),然后向有错误的表中添加一行
我使用tableModel.addRow(new Object[]{row,row});添加了一行TableModelListener来侦听插入事件。错误在TableModelListener中,这意味着我找不到刚才添加的行, java。lang.ArrayIndexOutofBounds异常:3
这是我的SSCCE,它是一个带有表格的对话框,单击“添加”按钮向表格中添加一行

import java.awt.BorderLayout;
import java.awt.FlowLayout;

import javax.swing.JButton;
import javax.swing.JDialog;
import javax.swing.JPanel;
import javax.swing.border.EmptyBorder;
import javax.swing.event.TableModelEvent;
import javax.swing.event.TableModelListener;
import javax.swing.table.DefaultTableModel;

import java.awt.GridLayout;
import javax.swing.JTable;
import java.awt.event.ActionListener;
import java.awt.event.ActionEvent;
import javax.swing.JScrollPane;

public class MainTable extends JDialog {


private static final long serialVersionUID = 156332386872772726L;

private final JPanel contentPanel = new JPanel();
private DefaultTableModel tableModel;
private JTable table;

public static void main(String[] args) {
    try {
        MainTable dialog = new MainTable();
        dialog.setDefaultCloseOperation(JDialog.DISPOSE_ON_CLOSE);
        dialog.setVisible(true);
    } catch (Exception e) {
        e.printStackTrace();
    }
}

public MainTable() {
    setBounds(100, 100, 450, 300);
    getContentPane().setLayout(new BorderLayout());
    contentPanel.setBorder(new EmptyBorder(5, 5, 5, 5));
    getContentPane().add(contentPanel, BorderLayout.CENTER);
    contentPanel.setLayout(new GridLayout(1, 0, 0, 0));
    {
        JScrollPane scrollPane = new JScrollPane();
        contentPanel.add(scrollPane);
        {
            table = new JTable();
            table.setAutoCreateRowSorter(true);
            tableModel = new DefaultTableModel(new String[]{"first","second"},0);
            table.setModel(tableModel);
            tableModel.addTableModelListener(new TableModelListener(){
                @Override
                public void tableChanged(TableModelEvent arg0) {
                    if(arg0.getType() == TableModelEvent.INSERT){
                        int row = arg0.getFirstRow();
                        System.out.println(table.getValueAt(row, 0));//bug!! I couldn't find the row I added.
                    }
                }
            });
            scrollPane.setViewportView(table);
        }
    }
    {
        JPanel buttonPane = new JPanel();
        buttonPane.setLayout(new FlowLayout(FlowLayout.RIGHT));
        getContentPane().add(buttonPane, BorderLayout.SOUTH);
        {
            JButton okButton = new JButton("Add");
            okButton.addActionListener(new ActionListener() {
                public void actionPerformed(ActionEvent arg0) {
                    int row = tableModel.getRowCount();
                    tableModel.addRow(new Object[]{row,row});//click button to add a row
                }
            });
            buttonPane.add(okButton);
            getRootPane().setDefaultButton(okButton);
        }
    }
}

}

我试过的

  • 将行索引转换为模型索引不起作用
  • 使用tableModel.insert()代替tableModel.add(),不起作用

共 (1) 个答案

  1. # 1 楼答案

    convert row index to model index doesn't work.

    TableModelListenerTableModel更改的侦听器。所以TableModelEvent中的索引是相对于TableModel

    System.out.println(table.getValueAt(row, 0));
    

    应该是:

    System.out.println(table.getModel().getValueAt(row, 0));
    

    TableModel获取数据

    或者,如果希望从JTable获取数据,则需要使用convertRowIndexToView(...)方法