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java为我的web应用编写授权过滤器(JSF2.0)

根据一些建议,我决定为我的web应用编写自己的授权过滤器(我没有使用容器管理的安全性,所以我必须这样做)

这是我的第一个过滤器,所以我对如何实现它有点困惑。 这就是我目前所做的:

package filters;

import java.io.IOException;

import javax.servlet.Filter;
import javax.servlet.FilterChain;
import javax.servlet.FilterConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;

import entities.Role;

public class RestrictPageFilter implements Filter {

    FilterConfig fc;

    public void init(FilterConfig filterConfig) throws ServletException {
        // The easiest way to initialize the filter
        fc = filterConfig;
    }

    public void doFilter(ServletRequest request, ServletResponse response,
            FilterChain chain) throws IOException, ServletException {

        HttpServletRequest req = (HttpServletRequest) request;
        HttpServletResponse resp = (HttpServletResponse) response;
        HttpSession session = req.getSession(true);
        String pageRequested = req.getRequestURL().toString();

        Role currentUser = (Role) session.getAttribute("userRole");

        //Pages that are allowed with no need to login:
        //-faq.xhtml
        //-index.jsp
        //-login.xhtml
        //-main.xhtml
        //-registration.xhtml

        //NOW pages that are restricted depending on the type of user
        //buyoffer.xhtml(Only BUYER)
        //sellerpanel.xhtml(Only SELLER)
        //adminpanel.xhtml(Only ADMINISTRATOR)

        //HOW SHOULD I IMPLEMENT THAT??
        if(currentUser != null && currentUser.getType().equals("BUYER")) {          

        }
        if(currentUser != null && currentUser.getType().equals("SELLER")) {         

        }
        if(currentUser != null && currentUser.getType().equals("ADMINISTRATOR")) {          

        }


    }

    public void destroy() {
        // Not needed
    }
}

正如你看到的,我在那里留下了我被卡住的评论。有人能帮我完成这个过滤器吗,或者给我一些伪代码提示我应该如何完成它

我在网上看到了一些例子,但是没有一个根据用户类型进行不同的过滤

我将感谢你的帮助:)

更新

我创建了一个xml文件来帮助我进行过滤(它位于WEB-INF/classes中)

<access>
    <buyer>
        <page>buyoffer.xhtml</page>
        <page>faq.xhtml</page>
        <page>index.jsp</page>
        <page>login.xhtml</page>
        <page>main.xhtml</page>
        <page>registrationSucceded.xhtml</page>     
    </buyer>
    <seller>
        <page>sellerpanel.xhtml</page>
        <page>faq.xhtml</page>
        <page>index.jsp</page>
        <page>login.xhtml</page>
        <page>main.xhtml</page>
        <page>registrationSucceded.xhtml</page>     
    </seller>
    <administrator>
        <page>sellerpanel.xhtml</page>
        <page>faq.xhtml</page>
        <page>index.jsp</page>
        <page>login.xhtml</page>
        <page>main.xhtml</page>
        <page>registrationSucceded.xhtml</page>     
    </administrator>
</access>

<!-- THE REGISTRATION PAGES SHOULD NOT BE ACCESSIBLE IF THE USER IS LOGGED IN -->

我从init()方法读取文件。()

public class RestrictPageFilter implements Filter {

    private FilterConfig fc;
private InputStream in;

    public void init(FilterConfig filterConfig) throws ServletException {
        // The easiest way to initialize the filter
        fc = filterConfig;
        //Get the file that contains the allowed pages
        in = this.getClass().getResourceAsStream("/allowedpages.xml");
    }

    public void doFilter(ServletRequest request, ServletResponse response,
            FilterChain chain) throws IOException, ServletException {

        HttpServletRequest req = (HttpServletRequest) request;
        HttpServletResponse resp = (HttpServletResponse) response;
        HttpSession session = req.getSession(true);
        String pageRequested = req.getRequestURL().toString();

        //Get the value of the current logged user 
        Role currentUser = (Role) session.getAttribute("userRole");
        if (currentUser != null) {

        }
    }

    public void destroy() {
        // Not needed
    }
}

共 (1) 个答案

  1. # 1 楼答案

    如果需要允许访问,只需调用

    // it will process request normally, means it will leave the control from Filter
    chain.doFilter(request, response);
    

    如果您想限制用户,请致电

    //take some action
    response.sendRedirect("URL to some page");//it will simply make user redirected 
    

    一些建议

    • 使用某种XML属性文件进行配置,我觉得你的代码很难,明天可能会添加另一个页面,所以你需要重新编译你的过滤器

    • 如果允许的话,只需使用SpringSecurity,它就有很好的特性。此外,您也不会重新发明车轮