在Java中基于所需长度的Concat输入数组

Question

我想根据特定长度连接输入数组，请帮助。在我的例子中，我需要连接长度<；=10，如果大于10，则需要转到下一个。。。请检查我的输入和预期结果，如下所示；多谢各位

输入=“欢迎”、“加入”、“java”、“世界”、“感谢”、“访问”、“我们的”、“世界”

预期结果=“欢迎来到”、“java世界”、“感谢”、“访问”、“我们的世界”

Answer 1

您可以实现一种按长度分隔的方法（即10）

主要内容：

import java.util.ArrayList;
import java.util.List;

public class ConcatArrayLength
{

    public static void main ( String [ ] args )
    {
        String[] input = { "Welcome","to","java","world","Thanks", "for", "visiting", "our", "World"};

        String [] output = concatByLength (input,  10 ); //separate by 10

        for( String outputElement : output )
        {
            System.out.println ( outputElement );
        }

    }

    private static String [] concatByLength (String[] input, int separator )
    {

        List < String > listString = new ArrayList< String > ( );

        String concatElement = "";

        for ( int i = 0; i < input.length; i++ )
        {
            //concat and trim
            concatElement = concatElement.concat ( input[i] + " " );
            concatElement.trim ( );
            //add if >= separator length
            if ( concatElement.length ( ) >= separator)
            {
                listString.add ( concatElement );
                concatElement = "";
            }
            //last element check
            else if( i == input.length-1)
            {
                listString.add ( concatElement );
            }
        }

        return listString.toArray ( new String[listString.size ( )] );
    }

}

示例输出：

只需更改行concatByLength (input, DESIRED_NUMBER );

10:

Welcome to 
java world 
Thanks for 
visiting our 
World 

15:

Welcome to java 
world Thanks for 
visiting our World

30:

Welcome to java world Thanks for 
visiting our World