如何在java中发送Https Post请求

Question

我想从java代码登录到应用程序。 这是我的密码

String httpsURL = "https://www.abcd.com/auth/login/";

String query = "email="+URLEncoder.encode("abc@xyz.com","UTF-8"); 
query += "&";
query += "password="+URLEncoder.encode("abcd","UTF-8") ;

URL myurl = new URL(httpsURL);
HttpsURLConnection con = (HttpsURLConnection)myurl.openConnection();
con.setRequestMethod("POST");

con.setRequestProperty("Content-length", String.valueOf(query.length())); 
con.setRequestProperty("Content-Type","application/x-www- form-urlencoded"); 
con.setRequestProperty("User-Agent", "Mozilla/4.0 (compatible; MSIE 5.0;Windows98;DigExt)"); 
con.setDoOutput(true); 
con.setDoInput(true); 

DataOutputStream output = new DataOutputStream(con.getOutputStream());  


output.writeBytes(query);

output.close();

DataInputStream input = new DataInputStream( con.getInputStream() ); 



for( int c = input.read(); c != -1; c = input.read() ) 
System.out.print( (char)c ); 
input.close(); 

System.out.println("Resp Code:"+con .getResponseCode()); 
System.out.println("Resp Message:"+ con .getResponseMessage()); 

但我不能登录，它只返回登录页面

如果有人可以，请帮助我理解我做错了什么

Answer 1

您可能会因为一些原因得到400，但通常是因为数据格式不正确（可能需要XML？）。也许已经有记录了。用邮递员试试看你得到了什么结果

Answer 2

错误：-（www-form中间有额外的空间）

con.setRequestProperty("Content-Type","application/x-www- form-urlencoded"); 

正确的

 con.setRequestProperty("Content-Type","application/x-www-form-urlencoded");