java如何在单独的类中使用getContentResolver（）

Question

我有一个从broadcastReceiver扩展而来的类，它给我提供GPS坐标。我想显示手机的序列号及其坐标

public class AlarmReceiver extends BroadcastReceiver{

long time = 10 * 1000; 

@Override
public void onReceive(final Context context, Intent intent) {

    LocationManager locationManager = (LocationManager)context
            .getSystemService(Context.LOCATION_SERVICE);

    Criteria criteria = new Criteria();

    String provider = locationManager.getBestProvider(criteria, true);

    locationManager.requestLocationUpdates(provider, time, minDistance, locationListener);

    Location location = locationManager.getLastKnownLocation(provider);

    String serialNumber = Build.SERIAL != Build.UNKNOWN ? Build.SERIAL :        Secure.getString(getContentResolver(), Secure.ANDROID_ID);   // returns device id of phone              

    String Text = "Latitude = " + location.getLatitude() +" Longitude = " location.getLongitude(); 

        Toast.makeText(context, Text, Toast.LENGTH_SHORT).show(); 

      } catch (Exception e) {
          Toast.makeText(context, "SMS faild, please try again.",
         Toast.LENGTH_LONG).show();
         e.printStackTrace();
      }
   }

    LocationListener locationListener = new LocationListener() {

    @Override
    public void onStatusChanged(String provider, int status, Bundle extras) {
    }

    @Override
    public void onProviderEnabled(String provider) {
    }

}

为了获取设备序列号，我使用了以下代码，但它显示了一个错误，即getContentResolver（）未定义。我已经搜索了解决方案，并尝试了getActivity（）和getApplicationContext（），但这对我不起作用

String serialNumber = Build.SERIAL != Build.UNKNOWN ? Build.SERIAL :       Secure.getString(getContentResolver(), Secure.ANDROID_ID);   // returns device id of phone 

Answer 1

嗯，应该是：

context.getContentResolver()

因为ContentResolver属于Context，并且Context通过回调传递

Answer 2

只需传递Context并用context.getContentResolver().调用它