多线程Java线程:竞争条件与同步
即使调用代码块是同步的,竞争条件也会发生。再想想,这似乎是一个锁的问题。请查看下面的简单代码块(代码将更好地解释它)-
class CriticalSectionTest {
public void initWithSync() {
final CriticalSection cSection = new CriticalSection();
Thread threadA = new Thread(new Runnable() {
@Override public void run() {
synchronized (cSection) {
cSection.add(2);
System.out.println(
"Value after adding from thread-A: " + cSection.getCount());
}
}
});
Thread threadB = new Thread(new Runnable() {
@Override public void run() {
synchronized (cSection) {
cSection.add(3);
System.out.println(
"Value after adding from thread-B: " + cSection.getCount());
}
}
});
threadA.start();
threadB.start();
//Desired output:
//A: 2
//B: 5
}
}
class CriticalSection {
private long count = 0;
public void add(long value) {
/* This method was not made synchronized, intentionally as its done in caller class
*/
this.count = this.count + value;
}
public long getCount() {
return count;
}
}
在多次运行时,它会打印以下输出-
这不好
Value after adding from thread-B: 3
Value after adding from thread-A: 5
看起来不错
Value after adding from thread-A: 2
Value after adding from thread-B: 5
有什么解释吗?还是我错过了一些基本的东西
# 1 楼答案
每个线程的开始顺序都不安全
Main
线程将一个接一个地启动线程,但没有任何东西阻止以下操作:threadB
有时可能在threadA
之前开始治疗,这就是你现在面临的问题