java如何从用户输入中找到最大值和最小值？（while循环）

Question

老实说，我不知道从哪里开始，我可以通过用户的输入找到平均值，但似乎无法从输入的数字中找出最大或最小的数字。有什么方法可以用吗？任何帮助都会很好。谢谢

编辑：有点想通了。然而，答案似乎总是最大的数=2.1478。。。或最小值=-2.1478

Scanner input = new Scanner(System.in);


System.out.println("Enter the number of grades: ");
double random = input.nextDouble();
double min = Integer.MIN_VALUE;
double max = Integer.MAX_VALUE;

double total=0;
int count = 1;
while (count < random+1) {




    System.out.println("Enter grade " + count + ":");

    double somenumber = input.nextDouble();
    total+=somenumber;

    count++;

    if (somenumber > max){
        max = somenumber;
    }
if (somenumber < min){
    min = somenumber;
}


}
System.out.println("Total is " + total);
System.out.println("Average is " + (total/random));
System.out.println("Largest number is " + max);
System.out.println("Smallest number is" + min);



        }

}

Answer 1

你想要一些看起来像

double min = Double.MAX_VALUE;
double max = 0.00;  // assume use positive numbers

while (count < random+1) {

System.out.println("Enter grade " + count + ":");

double somenumber = input.nextDouble();
total+=somenumber;

count++;

max = Math.max (somenumber, max);
min = Math.min (somenumber, min);

}

Answer 2

谢谢大家给我的建议。然而，当我运行我的程序时。我无法得到最大值和最小值的正确答案

编辑：解决了。谢谢大家的贡献&书信电报；33

Scanner input = new Scanner(System.in);


System.out.println("Enter the number of grades: ");
double random = input.nextDouble();
double min = Integer.MIN_VALUE;
double max = Integer.MAX_VALUE;

double total=0;
int count = 1;
while (count < random+1) {




    System.out.println("Enter grade " + count + ":");

    double somenumber = input.nextDouble();
    total+=somenumber;

    count++;

    if (somenumber > max){
        max = somenumber;
    }
if (somenumber < min){
    min = somenumber;
}


}
System.out.println("Total is " + total);
System.out.println("Average is " + (total/random));
System.out.println("Largest number is " + max);
System.out.println("Smallest number is" + min);



        }

}

最大的数字是2.14748最小的数字是-2.147478。。。这就是印刷出来的。。。我是不是犯了一个模拟错误