Java扫描器允许一定数量的INT

Question

真的很难找到答案

我正在创建一个游戏，它询问有多少玩家，用户可以输入的最大玩家数是3（1、2或3）。这是在创建for循环还是在scanner函数中输入一个参数

下面的代码：

System.out.println(" How many players are there? ");

int numberOfPlayers = scan.nextInt();

Player[] players = new Player[numberOfPlayers]; //this is where the players scores are stored
int currentPlayer = 0;  //because arrays start at 0: +1 is added

for (int i = 0; i < numberOfPlayers; i++) {

    System.out.println("What is player " + (i + 1) + " called?");
    String playerName = scan.next();
    players[i] = new Player(playerName);

Answer 1

我建议将Integer.parseInt(scan.nextLine())与循环一起使用，例如：

int numberOfPlayers = 0;
boolean correct = false;
do {
    try {
        System.out.println(" How many players are there? ");
        numberOfPlayers = Integer.parseInt(scan.nextLine());
        if (numberOfPlayers >= 1 && numberOfPlayers <= 3) {
            correct = true;
        }
    } catch (NumberFormatException e) {
    }
} while (!correct);

因此，如果用户输入了错误的数字或数字> 3或< 1，它将要求用户再次输入数字，直到用户输入正确的数字1,2,3