java JavaMail发件人地址被拒绝:访问被拒绝
好吧,我不知道还能做什么。这段代码在一周前我编写和测试时运行得非常好。然后我把它嵌入到我的程序中,意识到我不断地遇到异常。一切似乎都很正常。发件人地址是合法的。我用来测试它的收件人地址是合法的。怎么了?我很沮丧:
private String outgoingMailServer = "smtp.mail.yahoo.com";
boolean debug = true;
//set the host outgoing mail smtp server.
Properties properties = new Properties();
properties.put("mail.smtp.host", outgoingMailServer);
properties.put("mail.smtp.auth", "true");
Authenticator authenticator = new SMTPAuthentication();
Session session = Session.getDefaultInstance(properties, authenticator);
session.setDebug(debug);
//create a message session
Message msg = new MimeMessage(session);
//set the addresses, to and from
InternetAddress fromAddress;
fromAddress = new InternetAddress(emailFromAddress);
msg.setFrom(fromAddress);
//since mail can be sent to more than one recipient, create loop
//to add all addresses into InternetAddress, addressTo.
//InternetAddress[] toAddress = new InternetAddress[recipients.length];
InternetAddress[] toAddress = new InternetAddress[recipients.size()];
for (int i = 0; i < recipients.size(); i++) {
toAddress[i] = new InternetAddress(recipients.get(i));
}
msg.setRecipients(Message.RecipientType.TO, toAddress);
//set the subject and content type
msg.setSubject(emailSubject);
msg.setContent(actualMessage, "text/html; charset=utf-8");
//send the email
Transport.send(msg);
因此,例外情况如下:
javax.mail.SendFailedException: Invalid Addresses;
nested exception is:
com.sun.mail.smtp.SMTPAddressFailedException: 554 5.7.1 <blank@yahoo.com>: Sender address rejected: Access denied
at com.sun.mail.smtp.SMTPTransport.rcptTo(SMTPTransport.java:1835)
at com.sun.mail.smtp.SMTPTransport.sendMessage(SMTPTransport.java:1098)
at javax.mail.Transport.send0(Transport.java:195)
at javax.mail.Transport.send(Transport.java:124)
at internalLogicEngine.LogicEngine.sendReminder(LogicEngine.java:4282)
at testPackage.Test.main(Test.java:169)
Caused by: com.sun.mail.smtp.SMTPAddressFailedException: 554 5.7.1 <blank@yahoo.com>: Sender address rejected: Access denied
at com.sun.mail.smtp.SMTPTransport.rcptTo(SMTPTransport.java:1733)
... 5 more
任何帮助都将不胜感激。谢谢
# 1 楼答案
终于找到了解决办法(尽管我还是不明白为什么一开始就有问题,因为代码已经开始工作了。无论如何…)
你会发现问题中的代码与这些代码之间的主要区别是:
及
事实证明,必须使用正确的凭据(端口号、用户名、密码和邮件服务器)创建并连接
Transport
对象另外,我做了一个消除过程,发现只要你有这个:
你不需要这个:
上述情况也可以是:
不管怎样,这就是答案。你也可以修改gmail的答案。只要确保将发送邮件服务器更改为gmail,以及发件人的电子邮件地址、用户名和密码,您就会没事:)