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java InvokeLater冻结GUI

我试图用多线程来模拟一个简单的恒温器。恒温器应提高温度,以达到用户要求的值,即以下代码中的“最大”值。我有两个线程,一个负责提高温度,另一个负责降低温度。但降低的条件是,它应该只在燃气关闭时运行。但我在实施这个概念时遇到了一个问题。每次我按下Up按钮以增加所需的温度时,GUI都会冻结。我怎样才能解决这个问题

就像一根线抓住了锁,不会松开,但我怎么能注意到是哪根

`private volatile boolean isBoilerOn = false;
protected int Max, Current;
protected boolean isDone, isGasOn, isPumpOn;
private temperatureUp tempUp;
private temperatureDown tempDown;

public void setBoilerSatus(boolean status) {
    this.isBoilerOn = status;            
}

public boolean getBoilerStatus() {
    return this.isBoilerOn;           
}

private synchronized void setGasBoilerStatus() {
if(Max>Current)
    setBoilerSatus(true);
else
    setBoilerSatus(false);

notifyAll();
}

private void btnUpActionPerformed(java.awt.event.ActionEvent evt) {                                      
if(Max<=8)
{
    Max++;
    String strI = String.valueOf(Max);
    lblDesiredTemp.setText(strI);
    setGasBoilerStatus();
}
}                                     

private void btnDownActionPerformed(java.awt.event.ActionEvent evt) {                                        
if(Max>0)
{
    Max--;
    String strI = String.valueOf(Max);
    lblDesiredTemp.setText(strI);
    setGasBoilerStatus();
}
}                                       

private void formWindowActivated(java.awt.event.WindowEvent evt) {                                     
systemInitial();

tempUp = new temperatureUp();
tempDown = new temperatureDown();

tempUp.start();
tempDown.start();
}                                    

private synchronized void increaseTemeture() throws InterruptedException
{
while (!getBoilerStatus()) 
    wait();



if(Max>Current)
{
    Thread.sleep(4000);
    Current ++;
}

setGasBoilerStatus();
}

private synchronized void decreaseTemeture() throws InterruptedException
{
while(getBoilerStatus())    wait();

Thread.sleep(4000);
if(Current == 0 )
    return;

Current --;

setGasBoilerStatus();
}

private void systemInitial()
{
isGasOn = false;
Max = Current = 0;
}

class temperatureUp extends Thread 
{
@Override
public void run()
{
while(true)
{
    try
    {
        increaseTemeture();                    
    }
    catch(Exception ex)
    {
        StringWriter w = new StringWriter();
        ex.printStackTrace(new PrintWriter(w));
        txtLog.setText(w + "\n" + txtLog.getText());
    }
}
}
};

class temperatureDown extends Thread
{
@Override
public void run() 
{
    while(true)
    {
        try
        {
            decreaseTemeture();                    
        }
        catch(Exception ex)
        {
            StringWriter w = new StringWriter();
            ex.printStackTrace(new PrintWriter(w));
            txtLog.setText(w + "\n" + txtLog.getText());
        }
    }
}
};`

共 (1) 个答案

  1. # 1 楼答案

    这是因为您没有正确使用invokeLater。看看这里:Java AWT Threads