java从嵌套列表中获取最大值，并使用流将其转换为一个列表

Question

联盟有20个场地，球队有11个场地，球员有场地

 class Player {
        private int score;

        public int getScore() {
            return score;
        }
    }

    class Team {
        private List<Player> players;

        public List<Player> getPlayers() {
            return players;
        }
    }

    class League {
        private List<Team> teams;

        public List<Team> getTeams() {
            return teams;
        }
    }

需要从List<Team>最好的Player和最高的score中进行选择，并返回一个List<Player>，其中包括使用Stream从每个队中选出一名最好的球员

 public  List<Player> getTopPlayersFromEachTeam(List<Team> league) {
        // implementation
    }

被困在：

league.stream().map(Team::getPlayers).collect(Collectors.toList())

有什么提示吗

Answer 1

你可以做：

League league = new League(Arrays.asList(
        new Team(Arrays.asList(new Player(8), new Player(11))),
        new Team(Arrays.asList(new Player(15), new Player(12))),
        new Team(Arrays.asList(new Player(6), new Player(2), new Player(7)))
));

List<Player> bestPlayersInEachTeam = league.getTeams().stream()
        .map(team -> team.getPlayers().stream()        // Best from each team
                .max(Comparator.comparing(Player::getScore))
                .get())
        .collect(Collectors.toList());

System.out.println(bestPlayersInEachTeam);

输出：

[Player(score=11), Player(score=15), Player(score=7)]