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MySQL结果集JsonWriter:JsonWriter。值((java.sql.Date)结果集。getObject(列);

我想用

jsonWriter.value((java.sql.Date) resultSet.getObject(column));

但这似乎是不可能的。上面说long、Date和String都不适用于该类型。我怎样才能做到这一点

完整代码:

private static void writeField(final ResultSet resultSet, final JsonWriter jsonWriter, final ResultSetMetaData metaData, final int column) throws SQLException, IOException {
final int columnType = metaData.getColumnType(column);

switch ( columnType ) {
    case Types.BIT:
    case Types.TINYINT:
    case Types.SMALLINT:
        throw new UnsupportedOperationException("TODO: " + JDBCType.valueOf(columnType));
    case Types.INTEGER:
        jsonWriter.value((Integer) resultSet.getObject(column));
        break;
    case Types.BIGINT:
    case Types.FLOAT:
    case Types.REAL:
    case Types.DOUBLE:
    case Types.NUMERIC:
    case Types.DECIMAL:
    case Types.CHAR:
        throw new UnsupportedOperationException("TODO: " + JDBCType.valueOf(columnType));
    case Types.VARCHAR:
        jsonWriter.value((String) resultSet.getObject(column));
        break;
    case Types.LONGVARCHAR:
        jsonWriter.value((String) resultSet.getObject(column));
        break;
    case Types.DATE:
// here's the problem. i dont know to what to case the column.
        jsonWriter.value((java.sql.Date) resultSet.getObject(column));
        break;
    case Types.TIME:
    case Types.TIMESTAMP:
        jsonWriter.value((long) resultSet.getObject(column));
    case Types.BINARY:
    case Types.VARBINARY:
    case Types.LONGVARBINARY:
    case Types.NULL:
    case Types.OTHER:
    case Types.JAVA_OBJECT:
    case Types.DISTINCT:
    case Types.STRUCT:
    case Types.ARRAY:
    case Types.BLOB:
    case Types.CLOB:
    case Types.REF:
    case Types.DATALINK:
    case Types.BOOLEAN:
    case Types.ROWID:
    case Types.NCHAR:
    case Types.NVARCHAR:
    case Types.LONGNVARCHAR:
    case Types.NCLOB:
    case Types.SQLXML:
    case Types.REF_CURSOR:
    case Types.TIME_WITH_TIMEZONE:
    case Types.TIMESTAMP_WITH_TIMEZONE:
        throw new UnsupportedOperationException("TODO: " + JDBCType.valueOf(columnType));
    default:
        throw new UnsupportedOperationException("Unknown type: " + columnType);
    }
}

我还需要在以后实现时间戳——以防它们相关

非常感谢!:)


共 (1) 个答案

  1. # 1 楼答案

    好的,我终于找到了方法(我希望不是100%确定,因为我还不能在客户端上显示数据——但它可以编译并运行。下面是代码:

        case Types.DATE:
            java.sql.Date sqlDate = (java.sql.Date) resultSet.getObject(column);
            LocalDate localDate = sqlDate.toLocalDate();
            DateTimeFormatter formatDt = DateTimeFormatter.ISO_LOCAL_DATE;
            String formattedDate = localDate.format(formatDt);
            jsonWriter.value((String) formattedDate);
            break;
    

    我希望我没有以同样的方式格式化它两次?:)

    这里还有时间戳的代码:

    case Types.TIMESTAMP:
        java.sql.Timestamp sqlTimeStamp = (java.sql.Timestamp) resultSet.getObject(column);
        LocalDateTime localDateTime = sqlTimeStamp.toLocalDateTime();
        DateTimeFormatter formatTimestamp = DateTimeFormatter.ISO_LOCAL_DATE;
        String formattedDateTime = localDateTime.format(formatTimestamp);
        jsonWriter.value((String) formattedDateTime);
        break;