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eclipse java。util。NoTouchElementException错误?

我是一名Java程序员初学者,我试图制作一个程序,允许用户通过输入名称、数量和质量来制作水果对象。我用构造函数创建了一个单独的水果类。当我要求用户输入名称时,一切都很好,但当达到数量/质量时,我得到了一个java。util。NoTouchElementException运行时错误

这是我的密码

public class Fruit {

    String Name;
    int Quantity;
    double Mass;

    public Fruit (String Name, int Quantity, double Mass){
        this.Name = Name;
        this.Quantity = Quantity;
        this.Mass = Mass;
    }

    public void Information(){
        System.out.println("This fruit is an " + Name + " and there's " + Quantity + " of it");
    }
}

import java.util.Scanner;

public class Fruits {

    public static void main (String[] args){

        Fruit Apple = new Fruit("Apple", 5, 32.6);
        System.out.println (Apple.Name);

            System.out.println("What would you like to name the fruit?: ");
            Scanner name1 = new Scanner (System.in);
            String name = name1.nextLine();
            name1.close();

            System.out.println("How much fruits are there?: ");
            Scanner quant1 = new Scanner (System.in);
            int quantity = quant1.nextInt();
            quant1.close();

            System.out.println("What is the mass of the Fruit?: ");
            Scanner mass1 = new Scanner (System.in);
            double mass = mass1.nextDouble();
            mass1.close();

            Fruit newFruit = new Fruit (name, quantity, mass);

            newFruit.Information();

    }
}

共 (1) 个答案

  1. # 1 楼答案

    不需要创建多个扫描仪对象。当你关闭第一台扫描仪时,实际上你正在关闭System.in。所以第二个元素不能得到系统。在里面因此,最好使用单个扫描仪进行所有输入检索

            Scanner scanner = new Scanner (System.in);
            System.out.println("What would you like to name the fruit?: ");
            String name = scanner.nextLine();
            System.out.println("How much fruits are there?: ");
            int quantity = scanner.nextInt();
            System.out.println("What is the mass of the Fruit?: ");
            double mass = scanner.nextDouble();