java当我为登录用户创建会话时，如何在struts2中维护hibernate会话？

Question

我做了一个应用程序，因为我应该维护一个登录用户会话，我创建了一个登录拦截器来维护它。我继承了做hibernate会话的目的。当我使用登录拦截器和“hibernate default”时，它是抛出空指针异常。这里hibernate会话显示为空。如何维护休眠会话

下面是我的struts。xml

 <package name="helloworld" extends="hibernate-default">
    <interceptors>
        <interceptor name="mylogging" class="Demo.AuthenticationInterceptor"></interceptor>
        <interceptor-stack name="loggingStack">
            <interceptor-ref name="mylogging" />
            <interceptor-ref name="defaultStack" />                
        </interceptor-stack>
    </interceptors>
    <default-interceptor-ref name="loggingStack"></default-interceptor-ref>
    <action name="signin" method="checkLogin" class="Demo.LoginForm">
        <result name="input">/login.jsp</result>
        <result name="success" type="redirect">/list.jsp</result>
        <result name="failure">/error.jsp</result>
    </action>
    <action name="listUser" method="list" class="Demo.UserAction"> 
        <interceptor-ref name="basicStackHibernate"/>           
        <result name="success">/register1.jsp</result>
        <result name="login">/login.jsp</result>
    </action>
 </package>
</struts>     

我用于维护每个操作的会话，但我的会话显示为空

我的验证器。爪哇

public class AuthenticationInterceptor implements Interceptor
{
  public String intercept(ActionInvocation ai) throws Exception 
 {
    System.out.println("inside the interceptor()......new");
    Map session1 = ai.getInvocationContext().getSession();
    String name = (String) session1.get("name");
    System.out.println("inside the session or loginaction=" + name);
    if ((session1.get("name") != null) || (session1.get("name") == null))
   {
        System.out.println("inside the session or loginaction ");
        return ai.invoke();
    } else {
        return "login";
    }
}
}

例外情况是：

Session =null
java.lang.NullPointerException
at Demo.UserDAOImpl.listUser(UserDAOImpl.java:57)
at Demo.UserAction.list(UserAction.java:53)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at   sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
null
at java.lang.reflect.Method.invoke(Method.java:606)
at com.opensymphony.xwork2.DefaultActionInvocation.invokeAction(DefaultActionInvocation.java:440)
at com.opensymphony.xwork2.DefaultActionInvocation.invokeActionOnly(DefaultActionInvocation.java:279)
at com.opensymphony.xwork2.DefaultActionInvocation.invoke(DefaultActionInvocation.java:242)

Answer 1

使用basicStackHibernate拦截器是因为要执行列表、编辑和删除操作Hibernate access（会话和/或事务）

<interceptor-ref name="defaultStackHibernate" />