java如何在每次单击libgdx中的按钮时前后移动Sprite?
如何让我的玩家在自上而下的游戏中前后移动。我创建了两个按钮moveForward
按钮和moveBackward
按钮。我用acceleromter
左右移动我的播放器。我的主要问题是每当我点击按钮时,我的播放器就会前后移动。它使用上下键工作,但我不知道如何使用按钮触摸实现
下面是我的代码
// Load the sprite sheet as a texture
cat = new Texture(Gdx.files.internal("spriteCatsheet.png"));
catsprite = new Sprite(cat);
catsprite.setScale(2f);
player = new Rectangle();
player.x = Gdx.graphics.getWidth() - player.width - 350;
player.y = catPlayerY;
player.setWidth(25);
我的纽扣
//left_control
left_paw = new Texture(Gdx.files.internal("left_paw.png"));
myTextureRegion = new TextureRegion(left_paw);
myTexRegionDrawable = new TextureRegionDrawable(myTextureRegion);
moveBackward = new ImageButton(myTexRegionDrawable); //Set the button up
moveBackward.getStyle().imageUp = new TextureRegionDrawable(new TextureRegion(new Texture(Gdx.files.internal("left_paw.png"))));
//the hover
moveBackward.getStyle().imageDown = new TextureRegionDrawable(new TextureRegion(new Texture(Gdx.files.internal("left_paw_hover.png"))));
moveBackward.setPosition(10,25);
stage.addActor(moveBackward); //Add the button to the stage to perform rendering and take input.
Gdx.input.setInputProcessor(stage);
moveBackward.addListener(new InputListener(){
@Override
public void touchUp (InputEvent event, float x, float y, int pointer, int button) {
System.out.println("Left Button Pressed");
//Move player Backward
//player.y -= 300 * Gdx.graphics.getDeltaTime();
}
@Override
public boolean touchDown (InputEvent event, float x, float y, int pointer, int button) {
System.out.print("Released");
return true;
}
});
stage.addActor(moveBackward);
//right_control
right_paw = new Texture(Gdx.files.internal("right_paw.png"));
myTextureRegion = new TextureRegion(right_paw);
myTexRegionDrawable = new TextureRegionDrawable(myTextureRegion);
moveForward = new ImageButton(myTexRegionDrawable); //Set the button up
moveForward.getStyle().imageUp = new TextureRegionDrawable(new TextureRegion(new Texture(Gdx.files.internal("right_paw.png"))));
//the hover
moveForward.getStyle().imageDown = new TextureRegionDrawable(new TextureRegion(new Texture(Gdx.files.internal("right_paw-hover.png"))));
moveForward.setPosition(517,25);
stage.addActor(moveForward); //Add the button to the stage to perform rendering and take input.
Gdx.input.setInputProcessor(stage);
moveForward.addListener(new InputListener(){
@Override
public void touchUp (InputEvent event, float x, float y, int pointer, int button) {
System.out.println("Right Button Pressed");
//Move player Forward
//player.y += 300 * Gdx.graphics.getDeltaTime();
}
@Override
public boolean touchDown (InputEvent event, float x, float y, int pointer, int button) {
return true;
}
});
stage.addActor(moveForward);
渲染
spriteBatch.draw(currentFrame,player.x, player.y);
//On keyboard
if(Gdx.input.isKeyPressed(Input.Keys.DOWN))player.y -= 300 * Gdx.graphics.getDeltaTime();
if(Gdx.input.isKeyPressed(Input.Keys.UP)) player.y += 300 * Gdx.graphics.getDeltaTime();
if(Gdx.input.isKeyPressed(Input.Keys.LEFT)) player.x -= 300 * Gdx.graphics.getDeltaTime();
if(Gdx.input.isKeyPressed(Input.Keys.RIGHT)) player.x += 300 * Gdx.graphics.getDeltaTime();
//Mobile acceleration
if (Gdx.input.isPeripheralAvailable(Input.Peripheral.Accelerometer)) {
player.x -= Gdx.input.getAccelerometerX();
player.y += Gdx.input.getAccelerometerY() /1f;
}
if (player.x < 0) {
player.x = 0;
player.x += Gdx.graphics.getDeltaTime() *20 *delta;
}
if (player.x > Gdx.graphics.getWidth()-player.getWidth() -150) {
player.x = Gdx.graphics.getWidth()-player.getWidth() -150;
}
感谢您的支持和预付款^ u^
# 1 楼答案
您可以这样使用:
在
render()
方法中现在在Button的侦听器方法中
前进按钮的Do
# 2 楼答案
当按下按钮时,除了输出一些控制台文本外,您什么也不做。您应该在侦听器中调用一个方法来移动播放器
除此之外,触地是“刚触碰”,触地是“释放”。而不是相反。在您的情况下,您希望具有“按钮保持”功能,因此您需要为每个按钮设置一个标志,这些按钮在触地/刚按下时被激活,在触地/释放时被禁用。当标志处于激活状态时,这意味着按下按钮。然后在更新循环中,检查按钮/标志X是否被按下,并执行您的魔术