分析考试结果限制（Java）

Question

我是初学者，我正在做Deitel的练习如何编程我制作了一个程序来分析考试结果，并输出奖励给老师与否。我的程序运行良好，但我想，如果用户输入的值不是1或2，那么它应该给出一个错误，并终止程序

Following is the code:

    package test;
    import java.util.Scanner;
    public class apple {
        public static void main(String[] args) {
       Scanner input = new Scanner (System.in);
      int failure = 0;
      int passes = 0;
      int counter = 1;
      while (counter <= 10){
          System.out.print("Enter Result (For Pass Enter 1 or for Fail Enter 2): ");
          int result = input.nextInt();
          if (result == 1)
              passes = passes + 1;
          else 
              failure = failure + 1;
          counter = counter + 1;

      }
      System.out.printf("Total Pass Students are %d and Failed are %d" ,passes , failure );`enter code here`
      if (passes > 8)
          System.out.println("\nBonus to instructor");
        }
            }

Answer 1

为其他号码抛出一个异常如何？您可能应该使用自己的非通用异常，所以请用合适的类扩展异常替换它

      if (result == 1)
          passes = passes + 1;
      else if (result == 2)
          failure = failure + 1;
      else
          throw new Exception("Wrong value");