简单Java加密/解密（错误：意外类型| |必需：找到变量：值）

2 月，2 周 Questions & Answers 1036

我正试图帮助一位同事破解他朋友的一封信，他已经厌倦了自己做数学题。我借此机会尝试使用Java来帮助他在计算机进行运算的情况下更快地解密。起初我试着一次做5个字符的块，但我的数组太乱了，他认为他还是想一次做一个字符

下面是我的代码：

import java.io.*;
class CharlieEncryption
{
    public static void main(String args[]) throws IOException
    {
        CharlieEncryption app;
        app = new CharlieEncryption();
        app.appMain();
    }

    BufferedReader stdin;
    String inString;
    String encrypt;
    String decrypt;

    String[] alphabet = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","Y","X","Z"};
    String letter;
    int letter_code = 0;
    int number_code = 0;
    int letter_num = 0;
    int finish_letter_num = 0;
    String finish_letter;

    // appMain module (Call all modules here)
    public void appMain() throws IOException
    {
        Input();
        Mode();

        if(encrypt.equals("Y"))
        {
            Encrypt();
            Output();
        }
        else
        {
            Decrypt();
            Output();
        }
    }
    //Module to recieve Input
    void Input() throws IOException
    {
        //Requesting Input
            System.out.print("Please input character");
            letter = stdin.readLine();
        //Converting Letter to Number
            for(int j = 0; j < 25; j++)
            {
                if(letter.equals(alphabet[j]))
                {
                    letter_num = j;
                }
            }

        //Requesting Input for Code
            System.out.println("Please input code for the character");
            inString = stdin.readLine();
            number_code = Integer.parseInt(inString);               
    }

    //Module to ask if user wants to encrypt or decrypt
    void Mode() throws IOException
    {
        System.out.println("Would you like to encrypt? Y or N");
        encrypt = stdin.readLine();

        if(encrypt.equals("N"))
        {
            System.out.println("Would you like to decrypt? Y or N");
            decrypt = stdin.readLine();
        }
    }
    //Module to Encrypt Text
    void Encrypt()
    {
            (letter_num) + (number_code) = finish_letter_num;
        //Converting the finished number to a letter
        for(int i = 0; i < 25; i++)
        {
            if(finish_letter_num == i)
            {
                finish_letter = alphabet[i];
            }
        }           
    }
    //Module to Decrypt Text
    void Decrypt()
    {
            (letter_num) - (number_code) = finish_letter_num;
        //Converting the finished number to a letter
        for(int i = 0; i < 25; i++)
        {
            if(finish_letter_num == i)
            {
                finish_letter = alphabet[i];
            }
        }   
    }
    //Module to Output Encrypted Text OR Decrypted Text
    void Output()throws IOException
    {
            System.out.println("Result" + finish_letter);
    }

}

以下是错误：

    CharlieEncryption.java:78: error: unexpected type
            (letter_num) + (number_code) = finish_letter_num;
                         ^
      required: variable
      found:    value
    CharlieEncryption.java:91: error: unexpected type
            (letter_num) - (number_code) = finish_letter_num;
                         ^
      required: variable
      found:    value
    2 errors

试图用这个错误阅读所有其他人的问题只会让我头疼，因为我无法理解他们最初遇到问题的代码

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简单Java加密/解密（错误：意外类型| |必需：找到变量：值）

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