Java8流：在满足条件后收集元素

Question

我的建议如下

class EventUser {
  private id;
  private userId;
  private eventId;
}

我检索EventUser对象如下：

List<EventUser> eventUsers = eventUserRepository.findByUserId(userId);

假设“eventUsers”如下所示：

[
{"id":"id200","userId":"001","eventId":"1010"},
{"id":"id101","userId":"001","eventId":"4212"},
{"id":"id402","userId":"001","eventId":"1221"},
{"id":"id301","userId":"001","eventId":"2423"},
{"id":"id701","userId":"001","eventId":"5423"},
{"id":"id601","userId":"001","eventId":"7423"}
]

使用流媒体，并且不使用任何中间变量，我如何在给定EventUser之后过滤和收集事件。身份证件： 例：

List<EventUser> filteredByOffSet = eventUsers.stream.SOMEFILTER_AND_COLLECT("id301");

结果应该是：

[{"id":"id301","userId":"001","eventId":"2423"},
{"id":"id701","userId":"001","eventId":"5423"},
{"id":"id601","userId":"001","eventId":"7423"}]

Answer 1

如果不使用任何中间变量，就无法做到这一点。找到位置并迭代到最后（参见下面的问题，更准确地回答） enter link description here

Answer 2

使用Java9中的“dropWhile”