java如何一次退出所有多个嵌套方法
我一直在学习Tim Buchalka为软件开发人员开设的Java编程大师课程，并修改了第118课中的程序
我想在运行时使用列表迭代器（navigate方法）更新列表。程序运行正常，但如果我更新列表，Java会抛出一个错误：ConcurrentModificationException
我提出了以下解决方案： 每当用户修改列表时，都会运行其他方法，更新列表并将其传递给navigate（）方法。通过这样做，我的程序将进入多层嵌套方法，当用户想要退出程序时，问题就会出现（案例0:in navigate（）方法）。用户按0的次数与运行嵌套方法的次数相同
我最初的想法是计算navigate（）被嵌套的次数，然后使用for循环返回作为嵌套次数。但后来我明白了这毫无意义
我怎样才能使用case 0:一次退出程序
package com.practice;
import java.util.LinkedList;
import java.util.ListIterator;
import java.util.Scanner;
public class List extends Traveler {
private LinkedList<String> linkedList;
private String tripName;
public List(String travelerName, int travelerAge, String tripName) {//it has to have same amount of parameters or more with super constructor!
super(travelerName, travelerAge);
this.tripName = tripName;
this.linkedList = new LinkedList<>();
}
public List(){} //it has to have same amount of parameters or more with super constructor!
public LinkedList<String> getLinkedList() {
return linkedList;
}
public String getTripName() {
return tripName;
}
private void removeCity(LinkedList<String> cityList, String deletedCity) {
if(cityList.remove(deletedCity)) {
System.out.println(deletedCity + " has been removed");
} else System.out.println("Could not find the city you want to remove");
List.navigate(cityList);
}
//adds a new city and update the list without an error
private void noExceptionError(LinkedList<String> listOfCities, String cityName) {
ListIterator<String> listIterator = listOfCities.listIterator();
while((listIterator.hasNext())) {
int comparison = listIterator.next().compareTo(cityName);
if(comparison == 0) {
System.out.println(cityName + " has been already added to the list");
return;
} else if(comparison > 0) {
listIterator.previous();
break;
}
}
listIterator.add(cityName);
List.navigate(listOfCities);
}
private void loadToList(LinkedList<String> listOfCities) {
alphabeticallyAdd(listOfCities, "Poznan");
alphabeticallyAdd(listOfCities, "Gdansk");
alphabeticallyAdd(listOfCities, "Szczeczin");
alphabeticallyAdd(listOfCities, "Warszawa");
alphabeticallyAdd(listOfCities, "Lodz");
alphabeticallyAdd(listOfCities, "Wroclaw");
List.navigate(listOfCities);
}
private void alphabeticallyAdd(LinkedList<String> listOfCities, String cityName) {
ListIterator<String> listIterator = listOfCities.listIterator(); //just a setup; doesn't point to the 1st element
while((listIterator.hasNext())) {
//if value is greater, the word that is in the list is alphabetically bigger, thus, put it before the list element
//if equal, it is duplicate! return false
// else it is less, thus, we have to move further in the list
int comparison = listIterator.next().compareTo(cityName); //retrieves the 1st value and goes to the next
if(comparison == 0) {
System.out.println(cityName + " has been already added to the list");
return;
} else if(comparison > 0) {
listIterator.previous(); //because we've used .next() in the int comparison initialization
listIterator.add(cityName); //don't use linkedList.add because it doesn't know the int comparison, so cannot properly add!!!
return;
}
}
listIterator.add(cityName); //adding at the end of the list
}
public static void navigate(LinkedList<String> listOfCities) {
Scanner userChoice = new Scanner(System.in);
List travelListObject = new List();
ListIterator<String> listIterator = listOfCities.listIterator();
boolean goingForward = true;
while(true) {
Main.menu();
int choice = userChoice.nextInt();
userChoice.nextLine(); //takes care of enter key problem
switch(choice) {
case 0:
System.out.println("Goodbye");
//possible improvement
/* for(int i = 0; i <= List.amountNestedMethods; i++) {
return;
}*/
return;
case 1: //moving forward
if(!goingForward) {
if(listIterator.hasNext()) {
listIterator.next();
}
}
if(listIterator.hasNext()) {
System.out.println(listIterator.next());
Traveler.setNumberVisitedCities(Traveler.getNumberVisitedCities() + 1);
goingForward = true;
} else {
System.out.println("No more cities in the list");
goingForward = false;
}
break;
case 2: //moving back
if(goingForward) {
if(listIterator.hasPrevious()) {
listIterator.previous();
}
goingForward = false;
}
if(listIterator.hasPrevious()) {
Traveler.setNumberVisitedCities(Traveler.getNumberVisitedCities() + 1);
System.out.println(listIterator.previous());
} else {
System.out.println("You're at the beginning of the list");
goingForward = true;
}
break;
case 3:
Main.printCities(listOfCities);
break;
case 4:
break;
case 5:
System.out.println("Write new city");
String addedCity = userChoice.next();
travelListObject.noExceptionError(listOfCities, addedCity);
break;
case 6:
System.out.println("Write the city you want to delete");
String deletedCity = userChoice.next();
travelListObject.removeCity(listOfCities, deletedCity);
break;
case 7:
System.out.println("You have been in " + Traveler.getNumberVisitedCities() + " cities in total");
break;
case 9:
travelListObject.loadToList(listOfCities);
break;
default:
System.out.println("Something weird happened. Try to choose an option again");
}
}
}
}
# 1 楼答案
如果你想退出程序，你可以简单地调用系统。exit（n），其中n是一个整数返回码（约定为代码0表示正常执行，其他值表示某种错误）