java如何创建一个完美的延迟时间,使其只计算一次
你好,我正在使用一个jumpingApp,它会计算你跳了多少次,我正在使用加速计传感器。 我遇到的问题是,我真的不知道如何设置延迟,所以它是完美的,有时一个跳转算作两个跳转,有时它没有注册,有时它工作得很好。我希望每次计数跳跃都能有0.4秒左右的时间
private TextView textView;
private TextView text;
private SensorManager sensorManager;
double ax,ay,az;
boolean newJumpAccepted = true;
int numbersOfJumps = 0;
long startTime = 0;
int count;
MediaPlayer mediaPlayer;
Handler timerHandler = new Handler();
Runnable timerRunnable = new Runnable() {
@Override
public void run() {
long millis = System.currentTimeMillis() - startTime;
if(millis>400){
newJumpAccepted = true;
} else {
newJumpAccepted = false;
}
int seconds = (int) (millis / 1000);
int minutes = seconds / 60;
seconds = seconds % 60;
timerHandler.postDelayed(this,500);
}
};
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
sensorManager=(SensorManager) getSystemService(SENSOR_SERVICE);
sensorManager.registerListener(this, sensorManager.getDefaultSensor(Sensor.TYPE_ACCELEROMETER), SensorManager.SENSOR_DELAY_FASTEST);
text = (TextView) findViewById(R.id.text);
textView = (TextView) findViewById(R.id.textView);
}
@Override
public void onAccuracyChanged(Sensor arg0, int arg1) {
}
@Override
public void onSensorChanged(SensorEvent event){
SharedPreferences preferences = PreferenceManager.getDefaultSharedPreferences(this);
String result = "";
double d = Math.round(event.values[1]);
float threshold = preferences.getFloat("hello", 11);
if (d != 0 && d >= threshold && newJumpAccepted){
count++;
}
Log.i("hej", String.valueOf(d));
text.setText("Jump made" + " " + count + " " + d);
text.invalidate();
startTime();
}
private void startTime() {
if(newJumpAccepted) {
startTime = System.currentTimeMillis();
timerHandler.postDelayed(timerRunnable, 0);
}
newJumpAccepted = false;
}
}
# 1 楼答案