java如何抛出IOException？

Question

public class ThrowException {
    public static void main(String[] args) {
        try {
            foo();
        }
        catch(Exception e) {
             if (e instanceof IOException) {
                 System.out.println("Completed!");
             }
          }
    }
    static void foo() {
        // what should I write here to get an exception?
    }
}

嗨！我刚刚开始了解异常情况，需要了解一个问题，所以有谁能给我提供一个解决方案吗？ 我将非常感激。 谢谢

Answer 1

请尝试以下代码：

throw new IOException("Message");

Answer 2

static void foo() throws IOException {
    throw new IOException("your message");
}

Answer 3

try {
        throw new IOException();
    } catch(IOException e) {
         System.out.println("Completed!");
    }

Answer 4

I just started learning exceptions and need to catch an exception

抛出异常

throw new IOException("Something happened")

要捕获此异常，最好不要使用Exception，因为它非常通用，相反，要捕获您知道如何处理的特定异常：

try {
  //code that can generate exception...
}catch( IOException io ) {
  // I know how to handle this...
}