java无法分析字符串响应

Question

这是我试图解析的响应，并试图在单独的字符串中获取值

response = 
  "Data1{
      key1='4722**********6',
      key2='2107',
      key3=value{
           value1='226',
           value2=passed,
           value3=tracked,
           value4=noted
      },
      isChecked=true
  }"
      

但无法解析响应，比如

String Datas = "Data1{key1='4722**********6', key2='2107', key3=value{value1='226', 
              value2=passed,value3=tracked, value4=noted}, isChecked=true}";
String data = Datas.substring(5);
//String data1 = data.replaceAll("\"", "");
try {
    JSONObject dataObject = new JSONObject((data)); //JsonObject
    
    String strKey1= dataObject.getString("key1");
    String strKey2= dataObject.getString("key2");
    String strKey3= dataObject.getString("key3");

    JSONObject strValueObj = new JSONObject(strKey3);
    String strValue1= strValueObj.getString("value1");
    String strValue2= strValueObj.getString("value2");
    String strValue3= strValueObj.getString("value3");
    String strValue4= strValueObj.getString("value4");

正常的字符串解析是有效的，还是使用JSON解析是正确的？有人能帮我解析字符串响应吗

Answer 1

您可以对achive JSON格式进行一些数据转换：

private static final String KEY3 = "key3";
private static final String VALUE = "value";

void extractData() throws JSONException {
    String Datas = "Data1{key1='4722**********6', key2='2107', key3=value{value1='226', value2=passed,value3=tracked, value4=noted}, isChecked=true}";
    String data = Datas.substring(5);
    String dataAsJson = data.replaceAll("=", ":");
    
    if (dataAsJson.indexOf(KEY3) > -1) {
        StringBuilder dataBuilder = new StringBuilder(dataAsJson.replaceFirst(VALUE, "{" + VALUE + ":"));
        dataBuilder.insert(dataAsJson.indexOf("}", dataAsJson.indexOf(KEY3)) + KEY3.length() - 1, "}");
        dataAsJson = dataBuilder.toString();
    }
    JSONObject dataObject = new JSONObject((dataAsJson));
    String strKey1= dataObject.getString("key1");
    String strKey3= dataObject.getString("key3");

    JSONObject key3Obj = new JSONObject(strKey3);
    String value = key3Obj.getString("value");
    JSONObject valueObj = new JSONObject(value);
    String value1 = valueObj.getString("value1");
}

它可以工作，但肯定不是最优雅的解决方案，如果输入改变了它的结构，它也可能不起作用

编辑：新输入：

        String Datas = "Data1{key1='4722**********6', key2='2107', key3=value{value1='226', value2=passed,value3=tracked, value4=noted}, isMasked=true}";
    String data = Datas.substring(5);
    String dataAsJson = data.replaceAll("=", ":");

    if (dataAsJson.contains(KEY3)) {
        StringBuilder dataBuilder = new StringBuilder(dataAsJson.replaceFirst(VALUE, "{" + VALUE + ":"));
        dataBuilder.insert(dataAsJson.indexOf("}", dataAsJson.indexOf(KEY3)) + KEY3.length() - 1, "}");
        dataAsJson = dataBuilder.toString();
    }
    JSONObject dataObject = new JSONObject((dataAsJson));
    String strKey1 = dataObject.getString("key1");
    String strKey3 = dataObject.getString("key3");

    JSONObject key3Obj = new JSONObject(strKey3);
    String value = key3Obj.getString("value");
    JSONObject valueObj = new JSONObject(value);
    String value1 = valueObj.getString("value1");