参数无效的java HttpURLConnection GET调用

Question

我有一个非常简单的代码，它不起作用

Class-HttoCon:

package test;

import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLConnection;
import java.net.URLEncoder;

public class HttpCon {


public static void main(String[] args) {
    try {
        sendGet();
    } catch (Exception e) {
        e.printStackTrace();
    }
}
    // HTTP GET request
        private static void sendGet() throws Exception {

            String url = "http://myweb.com/public/resource/data/stream";

            URL obj = new URL(url);
            HttpURLConnection con = (HttpURLConnection) obj.openConnection();

            // optional default is GET
            con.setRequestMethod("GET");


            //add request header
            con.setRequestProperty("begin", "1430295300000");
            con.setRequestProperty("end", "1430297279988");
            con.setRequestProperty("id", "140621");
            con.setRequestProperty("time", "FIFTEEN_MINUTE");

            int responseCode = con.getResponseCode();
            System.out.println("\nSending 'GET' request to URL : " + url);
            System.out.println("Response Code : " + responseCode);

            BufferedReader in = new BufferedReader(
                    new InputStreamReader(con.getInputStream()));
            String inputLine;
            StringBuffer response = new StringBuffer();

            while ((inputLine = in.readLine()) != null) {
                response.append(inputLine);
            }
            in.close();

            //print result
            System.out.println(response.toString());

        }
}

错误跟踪：

{"fault":{"exceptionType":"MissingServletRequestParameterException","host":"12.205.101.123","cause":"Required Long parameter 'id' is not present","status":"400","query":"/public/resource/data/stream","stackTrace":"org.springframework.web.bind.MissingServletRequestParameterException: Required Long parameter 'id' is not present\n\tat org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter$ServletHandlerMethodInvoker.raiseMissingParameterException(AnnotationMethodHandlerAdapter.java:774)\n\tat org.springframework.web.bind.annotation.support.HandlerMethodInvoker.resolveRequestParam(HandlerMethodInvoker.java:509)\n\tat 

注意：

如果我直接在浏览器中点击url，效果会很好

http://myweb.com/public/resource/data/stream?begin=1430295300000&end=1430297279988&id=140621&time=FIFTEEN_MINUTE

更新：

使用curl：

curl -X GET http://myweb.com/public/resource/data/stream?begin=1430295300000&end=1430297279988&id=140621&time=FIFTEEN_MINUTE

上面的卷曲不起作用

curl -X GET 'http://myweb.com/public/resource/data/stream?begin=1430295300000&end=1430297279988&id=140621&time=FIFTEEN_MINUTE'

这个卷发很好用

Answer 1

创建一个包含参数的字符串，然后将其附加到URL上。从中创建URL Obj。例如：

String this.url = "http://myweb.com/public/resource/data/stream";
this.url += "?begin=1430295300000&end=1430297279988&id=140621
    &time=FIFTEEN_MINUTE"; 
this.urlObj = new URL(this.url);

然后创建连接，如原始示例所示

Answer 2

openConnection将建立连接并发出GET。返回的URLConnection对象上的GET参数的后续设置将被忽略，因为URL已经打开

将参数作为查询字符串参数添加到URL，就像上面的链接一样，然后打开该链接

或

尝试将参数发布到服务器（这样更好）