java处理周数并查找未来天数

Question

考虑到两个输入，我试图找到计算未来工作日的方法：

1. 当前工作日（范围为0-6，其中0为周日）
2. 从当前工作日开始执行多少计数（任意数字）
3. 这里，如果用户以前从当前工作日开始=3，并且 计数=7
4. 然后我预计它会回到3，类似的14或21
5. 如何对此进行推广，使计数在此固定范围内 0-6而不拔出

我已经做了一些code，发布在下面

public class ThoseDays {

    public static void main(String[] args) {

        Scanner obj = new Scanner(System.in);
        System.out.print("Enter number between 0-6 : ");
        int startFromHere = obj.nextInt();

        System.out.print("Enter number to count position from " + startFromHere + " : ");
        int rotateFromHere = obj.nextInt(); 


        System.out.print( startFromHere +  rotateFromHere);

        obj.close();
    }
}

实际结果：

> Enter the number between 0-6: 3
> Enter the number to count position from 3: 7
> 10

预期结果：

> Enter the number between 0-6: 3
> Enter the number to count position from 3: 7
> 3

Answer 1

嗨，我建议你在他们到达7天后用modulo来轮换Another tutorial here

public class ThoseDays {

  public static void main(String[] args) {

  //Scanner implements AutoCloseable
  //https://docs.oracle.com/javase/8/docs/api/java/lang/AutoCloseable.html
    try (Scanner obj = new Scanner(System.in)) { 
      System.out.print("Enter number between 0-6 : ");
      int startFromHere = obj.nextInt();

      System.out.print("Enter number to count position from " + startFromHere + " : ");
      int rotateFromHere = obj.nextInt();
      int absoluteNumber = startFromHere + rotateFromHere;
      System.out.println(absoluteNumber);
      int rotatedNumber = absoluteNumber % 7;
      System.out.println(rotatedNumber);
    }
  }
}

Answer 2

代码：

import java.util.*;
public class ThoseDays {

    public static void main(String[] args) {

        Scanner obj = new Scanner(System.in);
    System.out.println("note : 0:sun 1-6:mon-saturday");
        System.out.println("Enter the number between 0-6: ");// 0:sun 1-6:mon-saturday

        int startFromHere = obj.nextInt();

        System.out.println("Enter the number to count position from " + startFromHere+ ": ");
        int rotateFromHere =obj.nextInt();
        if(rotateFromHere%7==0)
        {
            System.out.println(startFromHere);
        }
        if(rotateFromHere%7!=0)
        {
       int dayOfWeek=(startFromHere+(rotateFromHere%7));
       if(dayOfWeek>=7)
       {
           System.out.println((dayOfWeek%7));
       }
       else
       {
           System.out.print(dayOfWeek);
       }
        }


        obj.close();
    }
}

通过改变条件和使用模来尝试这段代码，我会得到所有正确的结果

输出：
从这里开始=3
从这里旋转=7或14或21或7的倍数
提供与开始日期相同的日期

如果轮换日期为>；开始日期
例如：

startFromHere = 3 //wednesday
rotateFromHere = 11

输出将为：0，表示星期天

检查此代码，如果有用，请给我评分。谢谢