正在检查字典中是否存在节点值

Question

我正在尝试编写一个片段，用于在python中删除链表中的重复元素。你知道吗

我检查字典中以前的节点值的条件不是true。我不明白为什么它总是返回false。你知道吗

节点值为[0->；1->；2->；2->；3->；4->；4->；5

def RemoveRepeatNode(self):
    curr_node = self.head
    unique_list = {}
    unique_list[curr_node.data] = 1

    while(curr_node.next != None):
        if curr_node.next.data in unique_list: ## doesn't evaluate to True
            print "repeated values ", curr_node.next.data
            curr_node = curr_node.next.next
        else:
            unique_list[curr_node.data] = 1
            curr_node = curr_node.next

Answer 1

你的if子句也许可以，但你不需要重新链接。更改：

def RemoveRepeatNode(self):
    curr_node = self.head
    unique = {curr_node.data}  # better data structure: set

    while(curr_node.next != None):
        if curr_node.next.data in unique:
            curr_node.next = curr_node.next.next
            #        ^^^^^  relink!
        else:
            unique.add(curr_node.next.data) 
            # add .next.data         ^^^^^  that's the one you checked
            curr_node = curr_node.next