Python multiple if else函数并返回

Question

这在python上可能吗？你知道吗

def NearSourceFactor(seismic_source_distance,seismic_source_select): 
    Na = 0 
    if (seismic_source_distance <= 2) and (seismic_source_select == "A"):
        Na == 1.5
    elif (seismic_source_distance <= 5) and (seismic_source_select == "A"):
        return Na == 1.2
    elif (seismic_source_distance > 10) and (seismic_source_select == "A"):
        return Na == 1.0
    elif (seismic_source_distance <= 2) and (seismic_source_select == "B"):
        return Na == 1.3
    elif (seismic_source_distance <= 5) and (seismic_source_select == "B"):
        return Na == 1.0
    elif (seismic_source_distance > 10) and (seismic_source_select == "B"):
        return Na == 1.0
    elif (seismic_source_distance <= 2) and (seismic_source_select == "C"):
        return Na == 1.0
    elif (seismic_source_distance <= 5) and (seismic_source_select == "C"):
        return Na == 1.0
    elif (seismic_source_distance > 10) and (seismic_bldg_geometry == "C"):
        return Na == 1.0

Na = NearSourceFactor(seismic_source_distance,seismic_source_select) 

seismic_source是10，seismic_source_select=B，但不幸的是答案是“无”

我希望答案是1.0

Answer 1

def NearSourceFactor(seismic_source_distance,seismic_source_select): 

    if (seismic_source_distance <= 2) and (seismic_source_select == "A"):
        return 1.5
    elif (seismic_source_distance <= 5) and (seismic_source_select == "A"):
        return 1.2
    elif (seismic_source_distance > 10) and (seismic_source_select == "A"):
        return 1.0
    elif (seismic_source_distance <= 2) and (seismic_source_select == "B"):
        return 1.3
    elif (seismic_source_distance <= 5) and (seismic_source_select == "B"):
        return 1.0
    elif (seismic_source_distance >= 10) and (seismic_source_select == "B"):
        return 1.0
    elif (seismic_source_distance <= 2) and (seismic_source_select == "C"):
        return 1.0
    elif (seismic_source_distance <= 5) and (seismic_source_select == "C"):
        return 1.0
    elif (seismic_source_distance > 10) and (seismic_bldg_geometry == "C"):
        return 1.0

Na = NearSourceFactor(seismic_source_distance,seismic_source_select) 

我修复了它，所以它可以做你想要的，但请注意以下事项：

a）没有理由配置要返回的变量，只需返回值（例如，返回1）

b）写入Na==1.0时，实际上是在比较并接收布尔值。你知道吗

c）试着看看是否可以将逻辑更改为没有那么多if语句（似乎您的默认值为1，因此可以将所有内容放在else语句中（例如）