在字典中寻找相似之处

Question

我试图在多个.txt文件之间找到相似之处。我把所有这些文件都放在一本字典里，以文件名为关键字。你知道吗

当前代码：

import pandas as pd
from os import listdir, chdir, getcwd
path = (r'C:\...path')
chdir(path)
files = [f for f in listdir(path)]
files_dict = {}

for filename in files:
    if filename.lower().endswith(('.txt')):
        files_dict[str(filename)] = pd.read_csv(filename).to_dict('split')

for key, value in files_dict.items():
    print(key + str(value) +'\n')

本例中的键是文件名。值是标头和数据。 我想找出多个文件之间的值是否存在重复，这样我就可以在SQL中连接它们。我不知道怎么做

编辑示例文件：

timestamp,Name,Description,Default Column Layout,Analysis View Name
00000000B42852FA,ADM_EIG,Administratief eigenaar,ADM_EIG,ADM_EIG
000000005880959E,OPZ,Opzeggingen,STANDAARD,

根据代码：

Acc_ Schedule Name.txt{'index': [0, 1], 'columns': ['timestamp', 'Name', 'Description', 'Default Column Layout', 'Analysis View Name'], 'data': [['00000000B42852FA', 'ADM_EIG', 'Administratief eigenaar', 'ADM_EIG', 'ADM_EIG'], ['000000005880959E', 'OPZ', 'Opzeggingen', 'STANDAARD', nan]]}

编辑2：建议代码

for key, value in files_dict.items():
    data = value['data']
    counter = Counter([item for sublist in data for item in sublist])
    print([value for value, count in counter.items()])

输出：['00000000B99BD831', 5050, 'CK102', '0,00000000000000000000', 'Thuiswonend', 0, '00000000B99BD832', ........

Answer 1

Counter计算项目的频率，因此将告诉您任何出现多次的内容。从字典中取出data：

from Collections import Counter

data = [
   ['00000000B42852FA', 'ADM_EIG', 'Administratiefeigenaar', 'ADM_EIG', 'ADM_EIG'],
   ['000000005880959E', 'OPZ', 'Opzeggingen', 'STANDAARD', nan]
]

您需要展平列表列表：

[item for sublist in data for item in sublist]

计数器将为您提供每个项目的频率：

>>> Counter([item for sublist in data for item in sublist])
Counter({'ADM_EIG': 3, '00000000B42852FA': 1, 'Administratief eigenaar': 1, '000000005880959E': 1, 'OPZ': 1, 'Opzeggingen': 1, 'STANDAARD': 1, nan: 1})

然后您可以根据需要进行筛选：

counter = Counter([item for sublist in data for item in sublist])
[value for value, count in counter.items() if count > 1]

它给出了['ADM_EIG']

---

编辑以匹配问题编辑

要查看所有行，请获取所有数据并查找重复项：

data = []
for key, value in files_dict.items():
    data.extend(value['data'])

counter = Counter([item for sublist in data for item in sublist])
print([value for value, count in counter.items() if count > 1])