如何修复python中的（regex password）错误？

Question

我正在设置我的服务器，我想有复杂的密码。你知道吗

在Python中使用regex，如何验证用户的密码是：

至少8个字符

必须限于，但不特别要求：

大写字母：A-Z

小写字母：a-z

数字：0-9

任何特殊字符：@#$%^&；+=

import re

password = raw_input("Enter string to test: ")

if re.match(r'[A-Za-z0-9@#$%^&+=]{8,}', password):

    # match
else:

    # no match

from wtforms import StringField, PasswordField, SubmitField, BooleanField

from wtforms.validators import DataRequired, Length, Email, EqualTo, ValidationError


class RegistrationForm(FlaskForm):

    username = StringField('Username',
                           validators=[DataRequired(), Length(min=2, max=20)])
    email = StringField('Email',
                        validators=[DataRequired(), Email()])
    #password = 
    pattern = "^.*(?=.{8,})(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[@#$%^&+=]).*$"
    password = PasswordField('Password', validators=[DataRequired(), Length(min=2, max=20)])
    if re.match(r'[A-Za-z0-9@#$%^&+=]{8,}', password):
        print ("Valid password")
    else:
        print ("Password not valid")

我希望输出是有效或无效的密码

Answer 1

正则表达式对我来说有点重。您可以只使用普通的字符串操作：

from string import ascii_lowercase, digits

punctuation = '@#$%^&+='
valid_characters = ascii_lowercase + digits + punctuation

def validate_password(password):
    return len(password) >= 8 and set(password) <= set(valid_characters)