从特金特.ttk导入*干扰复选框

Question

我已经导入了from tkinter.ttk import *，所以我的下拉菜单可以正常工作，在这个模块中，下拉菜单不会复制某些选项，并使窗口成为其中文本的宽度。你知道吗

但是，对于moduleby复选框窗口不起作用，只显示一个空白窗口。 我该怎么做才能使两者都正常工作。你知道吗

下拉列表代码：

import random
from tkinter import *
from tkinter.ttk import *

with open('Comedy films', encoding='latin-1') as f:
    lines = f.readlines()
    value_fifteen_one=(random.choice(lines))
    value_fifteen_two=(random.choice(lines))
    value_fifteen_three=(random.choice(lines))
    value_fifteen_four=(random.choice(lines))
    value_fifteen_five=(random.choice(lines))

def menu_fifteen():      
    root15 = Tk()
    root15.title("Film choices")

    menu = Frame(root15)
    menu.pack(pady = 5, padx = 50)          
    var = StringVar(root15)

    options = [
            value_fifteen_one,
            value_fifteen_two,
            value_fifteen_three,
            value_fifteen_four,
            value_fifteen_five,
    ]
    option = OptionMenu(menu, var, options[0], *options, command=functionsfifteen)
    var.set('Select')
    option.grid(row = 1, column = 1)

    root15.mainloop()


def functionsfifteen(value):
    if value == value_fifteen_one:            
        print("Playing "+value_fifteen_one)
    if value == value_fifteen_two:            
        print("Playing "+value_fifteen_two)
    if value == value_fifteen_three:            
        print("Playing "+value_fifteen_three)
    if value == value_fifteen_four:            
        print("Playing "+value_fifteen_four)
    if value == value_fifteen_five:            
        print("Playing "+value_fifteen_five)

复选框代码：

def interests():
    check = Tk()
    check.title("Interests")

    CheckVar1 = BooleanVar()
    CheckVar2 = BooleanVar()
    CheckVar3 = BooleanVar()
    CheckVar4 = BooleanVar()


    C1 = Checkbutton(check, text = "Horror", variable = CheckVar1, \
                     onvalue = 1, offvalue = 0, height=1, \
                     width = 20)
    C2 = Checkbutton(check, text = "Action", variable = CheckVar2, \
                     onvalue = 1, offvalue = 0, height=1, \
                     width = 20)
    C3 = Checkbutton(check, text = "Science fiction", variable = CheckVar3, \
                     onvalue = 1, offvalue = 0, height=1, \
                     width = 20)
    C4 = Checkbutton(check, text = "Comedy", variable = CheckVar4, \
                     onvalue = 1, offvalue = 0, height=1, \
                     width = 20)

    def submitHandle():
        anyChecked = CheckVar1.get() | CheckVar2.get() | CheckVar3.get(
        ) | CheckVar4.get()
        if anyChecked:
            check.destroy()
        else:
            messagebox.showerror("Error", "Please check at least one.")

    submit_btn = Button(check, text="Submit", command=lambda: submitHandle()) #Submit button on the check button menu window


    C1.pack()
    C2.pack()
    C3.pack()
    C4.pack()
    submit_btn.pack()
    check.mainloop()


    if CheckVar1.get():
        filename = ("Horror");
        with open (filename, "a") as f:
            f.write("")

    if CheckVar2.get():
        filename = ("Action");
        with open (filename, "a") as f:
            f.write("")

    if CheckVar3.get():
        filename = ("Science fiction");
        with open (filename, "a") as f:
            f.write("")

    if CheckVar4.get():
        filename = ("Comedy");
        with open (filename, "a") as f:
            f.write("")

Answer 1

这就是为什么不应该进行通配符导入，尤其是使用tkinter和ttk。它们都导出具有相同名称的对象。你知道吗

最好的解决方案是更改导入，然后更改代码以匹配。你知道吗

import tkinter as tk
import tkinter.ttk as ttk
...
root15 = tk.Tk()
...