自动读取多个文件无需手动命名

Question

我有一个目录包含50个文件，我想读他们一个接一个和其他文件比较-这是固定的。我正在使用glob.blob。但没用。你知道吗

这里是我如何读取所有文件。相反，path = '*.rbd'如果我给出像path = run-01.rbd这样的文件名，它就工作了。你知道吗

path = '*.rbd'

path = folder + path
files=sorted(glob.glob(path))

完整代码

import glob
from itertools import islice
import linecache

num_lines_nonbram =  1891427

bits_perline = 32

total_bit_flips =  0

num_bit_diff_flip_zero = 0
num_bit_diff_flip_ones = 0
folder = "files/"

path = '*.rbd'

path = folder + path
files=sorted(glob.glob(path))

original=open('files/mull-original-readback.rbd','r')

#source1 = open(file1, "r")

for filename in files:
 del_lines = 101

 with open(filename,'r') as f:
  i=1
  while i <= del_lines:
   line1 = f.readline()
   lineoriginal=original.readline()
   i+=1
  i=0  
  num_bit_diff_flip_zero = 0
  num_bit_diff_flip_ones = 0
  num_lines_diff =0

  i=0
  j=0
  k=0
  a_write2 = ""
  while i < (num_lines_nonbram-del_lines):
        line1 = f.readline() 
        lineoriginal = original.readline() 
        while k < bits_perline:
                if ((lineoriginal[k] == line1[k])):
                     a_write2 += " "
                else:
                     if (lineoriginal[k]=="0"): 
                     #if ((line1[k]=="0" and line1[k]=="1")):

                      num_bit_diff_flip_zero += 1
                     if (lineoriginal[k]=="1"): 
                     #if ((line1[k]=="0" and line1[k]=="1")):

                      num_bit_diff_flip_ones += 1

                     #if ((line1[k]==1 and line1[k]==0)):
                      #a_write_file2 = str(i+1) + " " + str(31-k) + "\n" + a_write_file2
                      #a_write2 += "^"
                      #num_bit_diff_flip_one += 1
                   # else:
                    #    a_write2 += " " 
                k+=1


                total_bit_flips=num_bit_diff_flip_zero+num_bit_diff_flip_ones
        i+=1

        k=0
i = 0
print files
print "Number of bits flip zero= %d" %num_bit_diff_flip_zero +"\n" +"Number of bits flip one= %d" %num_bit_diff_flip_ones +"\n" "Total bit flips = %d " %total_bit_flips


f.close()
original.close()

Answer 1

问题是，无论何时开始与for filename in files:循环中的下一个文件进行比较，都不会返回到originalfile的开头。最简单的解决方案是：

original.seek(0)

在循环的开始。你知道吗

您还可以在循环之前将整个文件读入一个列表中一次，并使用它来代替重复读取文件。你知道吗

如果您只想处理部分文件，可以将文件读入一个列表，然后使用一个列表切片来获取所需的行。你知道吗

您也不应该每次通过循环都将num_bit_diff_flip_zero和num_bit_diff_flip_one设置为0，因为它们应该是所有文件的总数。你知道吗

with open('files/mull-original-readback.rbd','r') as original:
    original_lines = list(original)[del_lines:num_lines_nonbram]

for filename in files:
    with open(file, 'r') as f:
        lines = list(f)[del_lines:num_lines_nonbram]
    for lineoriginal, line1 in zip(original_lines, lines):
        for k in range(bits_perline):
            if lineoriginal[k] == line1[k]:
                a_write2 += " "
            elif lineoriginal[k] == "0"
                num_bit_diff_flip_zero += 1
            else:
                num_bit_diff_flip_ones += 1

total_bit_flips = num_bit_diff_flip_zero + num_bit_diff_flip_ones

Answer 2

您可以使用os模块首先列出目录中的所有内容（包括文件和模块），然后使用python生成器只过滤出文件。然后可以使用第二个python生成器过滤出具有特定扩展名的文件。可能有一种更有效的方法，但这是可行的：

import os

def main():

    path = './' # The path to current directory

    # Go through all items in the directory and filter out files
    files = [file for file in os.listdir(path) if 
os.path.isfile(os.path.join(path, file))]

    # Go through all files and filter out files with .txt (for example)
    specificExtensionFiles = [file for file in files if ".txt" in file]

    # Now specificExtensionFiles is a generator for .txt files in current
    # directory which you can use in a for loop
    print (specificExtensionFiles)


if __name__ == '__main__':
    main()

供进一步参考： How do I list all files of a directory?

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