first_name = input("Please enter your first name: ").capitalize()
start_inner = int(input("Hi {}, please enter the start value for the inner
loop: ".format(first_name)))
end_inner = int(input("Please enter the end value for the inner loop: "))
start_outer = int(input("Please enter the start value for the outer loop: "))
end_outer = int(input("Please enter the end value for the outer loop: "))
for outer in range(start_outer, end_outer):
for inner in range(start_inner, end_inner):
print("{:^2} {:^2}".format(outer, inner))
如果我把1(开始内部),3(结束内部),1(开始外部),2(结束外部)
我应该得到:
1 1
1 2
1 3
2 1
2 2
2 3
相反,我得到:
1 1
1 2
谢谢你的帮助。你知道吗
pythons
range(1,5)
对于结束项是非包含的,这意味着它将只从1循环到4。阅读有关此主题的更多信息here:-)@Cut7er是对的,但他的解决方案是:
我的解释:
range
包括第一个值range
排除第二个值见:this
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