使用BS4获取值

Question

我试图从我的soup中获取“dataval”，但它们都是一个巨大的列表，并不像网站上显示的那样格式化在不同的列表/列中。你知道吗

我知道标题在这里：

<th class="num record drop-3" data-tsorter="data-val">
    <span class="long-points">
     proj. pts.
    </span>
    <span class="short-points">
     pts.
    </span>
   </th>
   <th class="pct" data-tsorter="data-val">
    <span class="full-relegated">
     relegated
    </span>
    <span class="small-relegated">
     rel.
    </span>
   </th>
   <th class="pct" data-tsorter="data-val">
    <span class="full-champ">
     qualify for UCL
    </span>
    <span class="small-champ">
     make UCL
    </span>
   </th>
   <th class="pct sorted" data-tsorter="data-val">
    <span class="drop-1">
     win Premier League
    </span>
    <span class="small-league">
     win league
    </span>
   </th>

这就是我要尝试的：

url = 'https://projects.fivethirtyeight.com/soccer-predictions/premier-league/'
r = requests.get(url = url)
soup = BeautifulSoup(r.text, "html.parser")
table = soup.find("table", {"class":"forecast-table"})
#print(table.prettify())
for i in table.find_all("td", {"class":"pct"}):
     print(i)

理想情况下，我想要4个列表，包括类名和匹配的值

Answer 1

不完全确定您想要什么特定列，但这将获取标记属性中带有data-val的所有列：

import requests
from bs4 import BeautifulSoup

url = 'https://projects.fivethirtyeight.com/soccer-predictions/premier-league/'
r = requests.get(url)

soup = BeautifulSoup(r.text, "html.parser")
table = soup.find("table", {"class": "forecast-table"})

team_rows = table.find_all("tr", {"class": "team-row"})

for team in team_rows:
    print("Team name: {}".format(team['data-str']))

    team_data = team.find_all("td")

    for data in team_data:
        if hasattr(data, 'attrs') and 'data-val' in data.attrs:
            print("\t{}".format(data.attrs['data-val']))
    print("\n")

如果我确实正确理解了您的问题，那么您正在查找最后两个值，它们在html源代码中没有标记。在这种情况下，您可以尝试简单地查找tag[6]，虽然它当然不是很健壮—但是这是html解析，所以“不是很健壮”是imho课程的标准。你知道吗

我在这里要做的是查找所有团队行（由于类名的缘故，这很容易），然后简单地遍历团队行td中的所有tr标记。你知道吗