只使用“while”读取2个正整数并打印其前倍数的程序

Question

我试图写一个程序，读取2个正整数（m和n），然后只使用while循环打印m的n个第一个正整数。你知道吗

这是最初的问题

Write a program in the Python 3.x language that reads two positive integers, m and n, and print the first n positive integers that are multiples of m.

代码的输出应该如下所示：

Type a positive integer for m: 9 
Type a positive integer for n: 5 
The first 5 positive integers multiples of 9 are:
9
18
27
36
45

到目前为止我已经做了：

m = int(input("Type a integer for m: "))
n = int(input("Type a integer for n: "))
i = 1
print()
print("The first ",n,"positive integers multiples of ", m," are:")
while i <= n:
    m = m * i
    print(m)
    i = i + 1

我想了解如何解决这个问题，我意识到使用或如果它会更容易做到这一点

Answer 1

你的问题就在这条线上

m = m * i

您正在缓存一个中间值，然后在下一次迭代中将其相乘，因此第一次相乘的是m，但下一次迭代将相乘的是上一个中间值，而不是原始的m
您可以通过以下方式更改循环：

while i <= n:
    print(m * i)  #  you don't need to save the intermediate result, you can just print it
    i = i + 1

Answer 2

Nullman的asnwer是正确的，无论如何这里是您的代码更正，以防它可以帮助您更好地理解错误：

m = 9
n = 5
i = 1
print()
print("The first ",n,"positive integers multiples of ", m," are:")
while i <= n:
    multiple = m * i
    print(multiple)
    i = i + 1

您不能使用if，但确实可以使用for：

m = 9
n = 5
i = 1
print()
print("The first ",n,"positive integers multiples of ", m," are:")
for i in range(1, n + 1):
    multiple = m * i
    print(multiple)
    i = i + 1