擅长:python、mysql、java
<p>史蒂文的想法是对的。藏书库可以帮你搬东西。</p>
<p>如果您不想手工完成此项工作,您可以构建如下内容:</p>
<pre><code>data = [1,5,1,1,6,3,3,4,5,5,5,2,5]
counts = {}
for x in data:
if x not in counts.keys():
counts[x]=0
counts[x]+=1
tupleList = []
for k,v in counts.items():
tupleList.append((k,v))
for x in sorted(tupleList, key=lambda tup: tup[1]):
print "%s" % x[0],
print
</code></pre>