带词典的列表

2024-05-16 16:10:07 发布

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因此,我正在处理一个由字典及其相应值组成的列表。所以我的问题是,我如何才能使一个变量称为最大值的关键库存数字。可以选择最大值的if语句。我已经试过了:

最大值=0 对于牵引车的数量:

if "inventory_number" in cars:

   if int(cars['inventory_number']) >= int(max_value):

     max_value = int(cars['inventory_number'])

towed_cars=
[{"color":"RED",
"inventory_number":"2870803",
"make":"GMC",
"plate":"AX21690",
"state":"IL",
"style":"LL",
"tow_date":"2019-02-16T00:00:00.000",
"tow_facility_phone":"(773) 568-8495",
"towed_to_address":"10300 S. Doty"}
,
{"color":"SIL",
"inventory_number":"2870715",
"make":"CHEV",
"plate":"AV21919",
"state":"IL",
"style":"4D",
"tow_date":"2019-02-16T00:00:00.000",
"tow_facility_phone":"(773) 568-8495",
"towed_to_address":"10300 S. Doty"}]

Tags: numbermakeifvaluestylecarsmaxil
2条回答

您需要一个for循环来迭代它:

max_value = 0

for car in cars:
     if "inventory_number" in car:
         inventory_number = int(car['inventory_number'])
         if inventory_number > max_value:
              max_value = inventory_number

也可以使用generator comprehension

max(int(d.get('inventory_number', 0)) for d in towed_cars)

2870803

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