如何捕获文件中格式为（名称）：（句子）\n（名称）的所有句子：

Question

我有成绩单的档案

(name): (sentence)\n (<-- There can be multiples of this pattern)

(name): (sentence)\n
(sentence)\n

等等。我需要所有的句子。到目前为止，我已经得到它的工作硬编码的名称在文件中，但我需要它是通用的。你知道吗

utterances = re.findall(r'(?:CALLER: |\nCALLER:\nCRO: |\nCALLER:\nOPERATOR: |\nCALLER:\nRECORDER: |RECORDER: |CRO: |OPERATOR: )(.*?)(?:CALLER: |RECORDER : |CRO: |OPERATOR: |\nCALLER:\n)', raw_calls, re.DOTALL)

python3.6使用re。或者，如果有人知道如何使用spacy来实现这一点，那将是一个很大的帮助，谢谢。你知道吗

我只想在一个空语句之后获取\n，并将它放入它自己的字符串中。我想我只需要抓取最后给出的磁带信息，例如，因为我想不出一种方法来区分这句话是否是某人讲话的一部分。 有时，在行首和冒号之间有不止一个单词。你知道吗

模拟数据：

CRO: How far are you from the World Trade Center, how many blocks, about? Three or four blocks?

63FDNY 911 Calls Transcript - EMS - Part 1 9-11-01

CALLER:

CRO: You're welcome. Thank you.

OPERATOR: Bye.

CRO: Bye.

RECORDER: The preceding portion of tape concludes at 0913 hours, 36 seconds.

This tape will continue on side B.

OPERATOR NEWELL: blah blah.

Answer 1

您从未向我们提供模拟数据，因此我使用以下内容进行测试：

name1: Here is a sentence.
name2: Here is another stuff: sentence
which happens to have two lines
name3: Blah.

我们可以尝试使用以下模式进行匹配：

^\S+:\s+((?:(?!^\S+:).)+)

这可以解释为：

^\S+:\s+           match the name, followed by colon, followed by one or more space
((?:(?!^\S+:).)+)  then match and capture everything up until the next name

请注意，这将处理最后一句话的边缘大小写，因为上面使用的否定的lookahead将不是真的，因此将捕获所有剩余的内容。你知道吗

代码示例：

import re
line = "name1: Here is a sentence.\nname2: Here is another stuff: sentence\nwhich happens to have two lines\nname3: Blah."
matches = re.findall(r'^\S+:\s+((?:(?!^\S+:).)+)', line, flags=re.DOTALL|re.MULTILINE)
print(matches)

['Here is a sentence.\n', 'Here is another stuff: sentence\nwhich happens to have two lines\n', 'Blah.']

Demo

Answer 2

您可以使用先行表达式，该表达式在行首查找名称的相同模式，后跟冒号：

s = '''CRO: How far are you from the World Trade Center, how many blocks, about? Three or four blocks?
63FDNY 911 Calls Transcript - EMS - Part 1 9-11-01
CALLER:
CRO: You're welcome. Thank you.
OPERATOR: Bye.
CRO: Bye.
RECORDER: The preceding portion of tape concludes at 0913 hours, 36 seconds.
This tape will continue on side B.
OPERATOR NEWELL: blah blah.
GUY IN DESK: I speak words!'''
import re
from pprint import pprint
pprint(re.findall(r'^([^:\n]+):\s*(.*?)(?=^[^:\n]+?:|\Z)', s, flags=re.MULTILINE | re.DOTALL), width=200)

这将输出：

[('CRO', 'How far are you from the World Trade Center, how many blocks, about? Three or four blocks?\n63FDNY 911 Calls Transcript - EMS - Part 1 9-11-01\n'),
 ('CALLER', ''),
 ('CRO', "You're welcome. Thank you.\n"),
 ('OPERATOR', 'Bye.\n'),
 ('CRO', 'Bye.\n'),
 ('RECORDER', 'The preceding portion of tape concludes at 0913 hours, 36 seconds.\nThis tape will continue on side B.\n'),
 ('OPERATOR NEWELL', 'blah blah.\n'),
 ('GUY IN DESK', 'I speak words!')]