Python返回不真实的值？

Question

我是Python的新手，我正在用Python开发一个数字猜测游戏。但是，当我设置参数时：

import random
numberchosen = random.randint(0,100)
numberchosenstr = str(numberchosen)
print ("Let's play a number game")
numberguessed = input("Guess a number ")
print ("You guessed " + numberguessed)

if numberguessed > '100':
    print ("You guessed too high, choose a number below 100")

if numberguessed < '0':
    print ("You guessed too low, choose a number above 0")

if numberguessed != numberchosen:
    print ("wrong")

但是，当我运行模块，并选择数字5，例如，或任何数字是在正确的范围内，但不是正确的数字，它总是返回

Let's play a number game
Guess a number 5
You guessed 5
You guessed too high, choose a number below 100
wrong

所以，我的问题是，为什么Python返回>；100错误，有什么方法可以修复它？你知道吗

Answer 1

您正在比较字符串，这是按字典顺序（即按字母顺序，一次一个字符）进行的。但即使一是int，字符串也总是大于数字。您需要去掉比较号码上的引号，然后在input上调用int()，如下所示：

numberguessed = int(input("Guess a number "))  # convert to int
print ("You guessed {}".format(numberguessed)) # changed this too, since it would error

if numberguessed > 100:  # removed quotes
    print ("You guessed too high, choose a number below 100")

if numberguessed < 0:    # removed quotes
    print ("You guessed too low, choose a number above 0")