search.html
是显示搜索结果列表的页面,但当我单击“搜索”按钮时,它会显示一个错误页面“反向未找到”。。我在这里看到了相同的问题,但是代码不同,所以我没有找到解决问题的方法。你知道吗
def search(request):
if 'q' in request.GET and request.GET['q']:
q = request.GET['q']
words = word.objects.filter(title__icontains = q)
return render_to_response('dictionary/search.html',
{'words': words, 'query': q })
else:
return HttpResponse('Please submit a search term.')
def worder(request, word_id):
showword = get_object_or_404(word, id = word_id)
return render(request, 'dictionary/worder.html', {'showword': showword})
URL:
urlpatterns = [
url(r'^$', Dictionary.views.home, name='home'),
url(r'^about/$', Dictionary.views.about, name='about'),
url(r'^search/$', Dictionary.views.search, name='search'),
url(r'^worder/(?P<word_id>[0-9]+)/$', Dictionary.views.worder, name='worder')]
{% url 'worder' word_id %}
有问题:
<li class="listofwords"><a class="foundword" href="{% url 'worder' word_id %}">{{ word.title }}</a></li>
您使用的变量
word_id
不存在。您应该使用word.id
,它是对象词的id:相关问题 更多 >
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