不能纠正我在python3中的高低数字游戏吗？

Question

我有一个数字游戏的代码，我看不出我做错了什么，但每当我运行它告诉我，我太低，无论我选择什么数字。有人能告诉我我做错了什么吗？谢谢！另外，我知道有些部分可能是多余的，但我不知道它们是否真的停止了代码的工作。你知道吗

import random
print("Welcome, to the worst game you will ever play. For some reason, you've got to pick a number between 1 and 10. "
      "Pick 11, I dare you.")
print("The aim is to win with the lowest possible score.")
score = 0
player_attempts = 0
play = True

while play:
    computer_number = random.randint(1, 11)
    player_number = int(input("OK. What do you think the number is?"))
    player_number = int(player_number)

    while player_number != computer_number:

        if player_number == computer_number and player_attempts == 0:
                print("Wow. You actually did it. And it only took you " + 
                      str(player_attempts) + "try. I'm impressed. I thought you were just one of those weirdos who "
                      "downloads a dodgy free game to escape from society...")
                score += 1
                player_attempts += 1
                print("Your score is " + str(score) + ". Maybe. I could be lying. How would you know?")
                play = False

        elif int(player_number) == int(computer_number) and int(player_attempts) >= 0:
                    print("Wow. You actually did it. And it only took you " + str(player_attempts) +
                          "tries. I'm impressed. I thought you were just one of those weirdos who "
                          "downloads a dodgy free game to escape from society...")
                    score += 1
                    player_attempts += 1
                    print("Your score was " + str(score) + ". Maybe. I could be lying. How would you know?")
                    play = False

        elif int(player_number) > int(computer_number):
            print("You overshot. But really, does it matter? You should stop, get out of the basement, enter society. "
                  "Or have another go.")
            score += 1
            player_attempts += 1
            print("Your score is " + str(score) + ".")
            again = str(input("Try again."))
            if again == "no":
                play = False
            elif again == "yes":
                play = True

        elif int(player_number) < int(computer_number):
            print("You were too low. Underachieving. Sound familiar?")
            score += 1
            player_attempts += 1
            print("Your score is " + str(score) + ".")
            again = str(input("Try again."))
            if again == "no":
                play = False
            elif again == "yes":
                play = True

        elif int(player_number) == 11:
            print("Wow. You really chose 11. You are actually more intelligent than I had originally thought...")
            again = str(input("Try again."))
            if again == "no":
                play = False
            elif again == "yes":
                play = True

Answer 1

对于计算机来说，不可能产生真正的随机数。相反，我们使用一个名为seeding的方法将一个不断变化的值（如当前时间）输入到随机数生成器，这样它每次都返回不同的值。你知道吗

修改while循环以为random生成器对象播种，如下所示：

while play:
    random.seed()
    # This seeds the random number generator with the system time.
    computer_number = random.randint(1, 11)
    player_number = int(input("OK. What do you think the number is?"))
    ...

这应该用系统时间初始化random对象，这样每次执行代码都会产生一个不同的伪随机值。你知道吗

Answer 2

我注意到一件事

    while player_number != computer_number:

         if player_number == computer_number and player_attempts == 0:
            print("Wow. You actually did it. And it only took you " + 
                  str(player_attempts) + "try. I'm impressed. I thought you were just one of those weirdos who "
                  "downloads a dodgy free game to escape from society...")
            score += 1
            player_attempts += 1
            print("Your score is " + str(score) + ". Maybe. I could be lying. How would you know?")
            play = False

         elif int(player_number) == int(computer_number) and int(player_attempts) >= 0:
                print("Wow. You actually did it. And it only took you " + str(player_attempts) +
                      "tries. I'm impressed. I thought you were just one of those weirdos who "
                      "downloads a dodgy free game to escape from society...")
                score += 1
                player_attempts += 1
                print("Your score was " + str(score) + ". Maybe. I could be lying. How would you know?")
                play = False

因为前两个if语句永远不会执行，因为while player_number != computer_number:与前两个条件冲突。你知道吗

Answer 3

您的代码结构如下所示

while play:
    computer_number = randomnumber
    player_number = inputnumber

    while player_number != computer_number:    #not equal
        if condition1:
            congratulation
        elif condition2:
            be sarcastic
        elif condition3:
            be even more sarcastic

现在，如果你马上猜出这个数字，你就避开了内部的while循环，转到下一个计算机生成的随机数。但是如果你选择了一个不同于计算机的数字，你就进入了内部循环，你永远被困在那里，因为你不改变player_number或computer_number。解决方案是什么？去掉内环。这是完全没有必要的，因为您可以用if-elif构造检查这个条件。你知道吗

另一方面，赋值变量input()已经是一个字符串变量，不需要用str(input()转换它。如果您将带有int(input())的输入转换成一个整数，那么您就不必在调用这个整数变量时反复进行这个整数转换。你知道吗