python面向对象编程类型：列表对象不是卡拉布吗

Question

class y():
    def __init__(self,favourite_channels = [""]):

        self.favourite_channels= favourite_channels
    def favourite_channels(self,i):
        print("Ur Favourite Channel=",i)
        self.favourite_channels.append(i)
x = y()
print("""*******************

1. Favourite Channel
press q to the exit
*******************""")

while True:

    a = input("Select : ")
    if a=="1":
        channels=input("Your fav channels use , to the split")
        addable_channels =channels.split(",")
        for i in addable_channels:
            x.favourite_channels(i)


    elif a=="q":
        break
    else:
        print("İnvalid Number")

Answer 1

如果您只在列表的末尾加了大括号（x.u channels是list），则会出现这样的错误。 如果你想要列表x.favorite\u频道的第i个元素，你应该写x.favorite\u频道[i-1]。你知道吗