每64个字符插入换行符

Question

有人能给我指出正确的方向吗。。你知道吗

我有一个包含单词句子的字符串 e、 g.“他试图学习一种pythonic，或者regex，解决问题的方法”

这个字符串非常大，我需要把它分成多行，每行不能超过64个字符。 但我不能每64个字符插入一个换行符。我需要确保换行符出现在第64个字符之前最接近的字符（来自一组字符）处，以确保行不超过64个字符。 e、 我只能在空格、逗号或句号后插入换行符

我还需要解决方案是相当有效的，因为这是一个行动，将发生很多次。你知道吗

使用textwrap

我不确定textwrap是否是解决问题的方法，因为我需要保留输入字符串中的原始换行符。 示例：

long_str = """
123456789 123456789 123456789 123456789 123456789 123456789
Line 1: Artificial intelligence (AI), sometimes called machine intelligence, 
Line 2: is intelligence demonstrated by machines, 
Line 3: in contrast to the natural intelligence displayed by humans and  other animals. 
Line 4: In computer science AI research is defined as
"""
lines = textwrap.wrap(long_str, 60, break_long_words=False)
print('\n'.join(lines))

我想要的是：

123456789 123456789 123456789 123456789 123456789 123456789
Line 1: Artificial intelligence (AI), sometimes called 
machine intelligence, 
Line 2: is intelligence demonstrated by machines, 
Line 3: in contrast to the natural intelligence displayed 
by humans and other animals. 
Line 4: In computer science AI research is defined as

但是textwrap给了我这个：

 123456789 123456789 123456789 123456789 123456789 123456789
Line 1: Artificial intelligence (AI), sometimes called
machine intelligence,  Line 2: is intelligence demonstrated
by machines,  Line 3: in contrast to the natural
intelligence displayed by humans and other animals.  Line 4:
In computer science AI research is defined as

我怀疑Regex可能是答案，但我在试图用Regex解决这个问题时已经超出了我的深度。你知道吗

Answer 1

import textwrap

def f1(foo): 
    return iter(foo.splitlines())

long_str = """
123456789 123456789 123456789 123456789 123456789 123456789
Line 1: Artificial intelligence (AI), sometimes called machine intelligence, 
Line 2: is intelligence demonstrated by machines, 
Line 3: in contrast to the natural intelligence displayed by humans and  other animals. 
Line 4: In computer science AI research is defined as
"""
[print('\n'.join(textwrap.wrap(l, 64, break_long_words=False))) for l in f1(long_str)]

每this