擅长:python、mysql、java
<pre><code>constants = [1,2,3]
integrals = [] #alternatively {}
from scipy import integrate
def f(x,c):
2*x*c
for c in constants:
integral, error = integrate.quad(lambda x: f(x,c),0.,1.)
integrals.append(integral) #alternatively integrals[integral]
</code></pre>
<p>这将为任何常量列表输出一个与Nicolas answer相同的列表。</p>