擅长:python、mysql、java
<p>在<code>urls.py</code>中,需要正确导入视图:</p>
<pre><code>from django.conf.urls import patterns, url
from yourapp.views import test
urlpatterns = patterns('',
url(r'$', test.as_view(), name='test'),
)
</code></pre>
<p>在您看来,您需要修复类,因此:</p>
<pre><code>class test(TemplateView):
template_name = 'myapp/test.html'
</code></pre>
<p>您不应该使用<a href="https://docs.djangoproject.com/en/1.6/ref/class-based-views/mixins-simple/#django.views.generic.base.TemplateResponseMixin.get_template_names" rel="nofollow">^{<cd2>}</a></p>
<p>如果这确实是您要做的所有事情(即,呈现模板),那么您可以直接在您的应用程序中导入TemplateView网址.py地址:</p>
<pre><code>from django.conf.urls import patterns, url
# from yourapp.views import test
from django.views.generic.base import TemplateView
urlpatterns = patterns('',
url(r'$', TemplateView.as_view(template_name='myapp/test.html'), name='test'),
)
</code></pre>