我想通过url传递一个列表。但当我尝试的时候,我犯了一些错误。我怎么能这么做。有人请帮帮我。。
这是我的观点
def add_student(request):
if request.method == 'POST':
student_list = []
student_name = request.POST.getlist('student_name')
student_phone = request.POST.getlist('student_phone')
zipped = zip(student_name,student_phone)
for student_name,student_phone in zipped:
student_object = Student(
student_name=student_name,
student_phone=student_phone
)
student_object.save()
student_list.append(student_object.id)
return HttpResponseRedirect(reverse('students:view_students', args=student_list))
**# in the above code it throwing some errors**
else:
return render(request,'students/add_student.html')
def view_students(request,student_list=None):
if student_list:
instances = Student.objects.filter(id__in=student_list)
else:
instances = Student.objects.filter()
context = {}
context['instances'] = instances
return render(request,'students/view_all_student.html',context)
这是我的网址:
url(r'^view-students/(?P<student_list>\w+)/$',views.view_students, name='view_students'),
这就是我犯的错误。
NoReverseMatch at /app/product/add-product/
Reverse for 'view_products' with arguments '(14, 15)' and keyword arguments '{}' not found. 1 pattern(s) tried: [u'app/product/view-products/(?P<pd_list>.*)/$']
这里(14,15)是列表项。
如果问题不对。有人请纠正这个问题。
如果你只想呈现一个列表,你就应该这样做。
但是,您的问题似乎与用户重复发布此请求有关。要解决这个问题,可以将它们作为get参数传递
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