如何在python中将dict作为值添加到键

Question

我有一个口述是-team={ludo:4,monopoly:5}

我怎样才能形成一个新的dict，它有一个名为board_games的键，值是另一个dict，它有一个键，上面的团队dict应该是-

new_team = { board_games : {junior:{ludo:4,monopoly:5}}}

基本上我是想做点像perlish的事-

new_team['board_games']['junior'] = team

Answer 1

基本问题是，在您要编写的代码中，尝试访问new_team['board_games']，而不首先给它赋值。dict不支持这一点。你知道吗

如果您坚持一定要写new_team['board_games']['junior'] = team，那么有几种方法：

1）创建所需密钥：

new_team = { 'board_games' : dict() }
new_team['board_games']['junior'] = team

或者：

new_team = dict()
new_team['board_games'] = dict()
new_team['board_games']['junior'] = team

甚至：

new_team = dict();
new_team.setdefault('board_games', dict())
new_team['board_games']['junior'] = team

2）使用defaultdict：

import collections
new_team = collections.defaultdict(dict)
new_team['board_games']['junior'] = team

Answer 2

我看不出问题所在：

>>> team = {"ludo": 4, "monopoly": 5}
>>> new_team = {"board_games": {"junior": team}}
>>> new_team
{'board_games': {'junior': {'ludo': 4, 'monopoly': 5}}}

如果您想动态构造它，^{}就是您需要的：

>>> from collections import defaultdict
>>> new_dict = defaultdict(dict)
>>> new_dict['board_games']['junior'] = team
>>> new_dict
defaultdict(<type 'dict'>, {'board_games': {'junior': {'ludo': 4, 'monopoly': 5}}})